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miskamm [114]
3 years ago
7

How are the functions f(x) = 16* and 19(x) = 161/2 related?

Mathematics
1 answer:
trapecia [35]3 years ago
3 0

Answer:

F(x) = 16^x = 8^2x

g(x) = 16^1/2x = 8^x

So you can see the relationship. They are all of the type a^bx form, with same base of a, f(x) will have larger increasing rate.

Step-by-step explanation:

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Vinil7 [7]

Answer:

V=4/3 π r ^3 is the answer

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3 years ago
Which correlation coefficient indicated the strongest linear relationship between the variables?
Anna35 [415]

Answer:

-0.87 has the strongest linear relationship

Step-by-step explanation:

-0.87, since it is the closest value to either one or negative one,

0.8 is the second strongest

0.65 is the third strongest

-0.52 is the least strongest

7 0
3 years ago
Find the measures of the following angles.
makvit [3.9K]

Answer:

1: 36° 2: 122° 3: 122° 4: 38°

Step-by-step explanation:

First start out by getting 2 and 3. so 58+angle 3 has to sum to 180° since they are supplementary and are a straight line. So 180-58=122. Angle 2 is the same since theyre vertical. then since a triangle has 180° total, you subtract from 180 to find the final angle measurement.

5 0
3 years ago
Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

  • \mathbf{AB = 3\sqrt{2}}
  • AB and CD are not congruent
  • AB does not bisect CD
  • CD does not bisect AB

<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0
3 years ago
HELP 20 pts IF ANSWERED (SHOW YOUR WORKKK!) please.<br> 3+y/4 = -y/8
Lera25 [3.4K]
I got you sis :)

3+y/4=-y/8
Multiply thru by 8 to get:
24 + 2y = -y
3y = -24
y = -8

5 0
3 years ago
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