ចំនុចរូបធាតុមួយចរពាក់កណ្តាលដំបូងនៃចម្ងាយចររបស់វាដោយល្បឿនប, = 2 m/s ហើយកំណាត់ផ្លូវ

If a 0.15 kg ball falls and has a KE of 20 J just before striking the ground, from what height did it fall. A. 1.36m B. 3m C. 13

RUDIKE [14]

According to the conservation of mechanical energy, the kinetic energy just before the ball strikes the ground is equal to the potential energy just before it fell.

Therefore, we can say KE = PE
We know that PE = m·g·h

Which means KE = m·g·h

We can solve for h:

h = KE / m·g
= 20 / (0.15 · 9.8)
= 13.6m

The correct answer is: the ball has fallen from a height of 13.6m.

5 0

3 years ago

I will give you branilest

morpeh [17]

Answer:

Explanation:

if you bounce a tennis ball, it will come back up as an equal reaction to your action (dropping it). there is an equal but opposite reaction in this scenario, demonstrating newton's third law.

6 0

4 years ago

Read 2 more answers

A parallel-plate vacuum capacitor has 8.38 j of energy stored in it. the separation between the plates is 2.30 mm. if the separa

avanturin [10]

<h3><u>Answer;</u></h3>

= 4.19 Joules

<h3><u>Solution;</u></h3>

Energy stored in capacitor = U = 8.38 J

U =(1/2)CV^2

C =(eo)A/d

C*d=(eo)A=constant