If a 0.15 kg ball falls and has a KE of 20 J just before striking the ground, from what height did it fall. A. 1.36m B. 3m C. 13
1 answer:
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Answer : The value of equilibrium constant for the following reaction will be, 2.4
Explanation : Given,
Initial concentration of = 0.45 M
Equilibrium concentration of = 0.30 M
is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The given balanced equilibrium reaction is,
As we know that the concentrations of pure solids are constant that means they do not change. Thus, they are not included in the equilibrium expression.
Actual concentration of at equilibrium =
Concentration of at equilibrium =
The expression for equilibrium constant for this reaction will be,
Now put all the given values in this expression, we get :
Therefore, the value of equilibrium constant for the following reaction will be, 2.4
Answer:
r = 29.53 degrees
Explanation:
Given that,
Angle of incidence,
We need to find the angle at which it will travel in the water. The refractive index of water is 1.33 and refractive index of air is 1. Using Snell's law as :
r is the angle of refraction
So, the ray will travel at an angle of 29.53 degrees in the water.