Answer:
A
Explanation:
this because
gravitational potential energy = mass x height x gravitational field strength
so let's assume mass is 2 kg and gravitational field strength is 10 N /kg
so when height is very low, take it as 3 m
gravitational potential energy= 2 x 3 x 10 = 60 j
but when height is 6m
gravitational potential energy = 2 x 6 x 10 = 120 j
so when the height is the greatest, the gravitational potential energy is the highest
so A is the heighest so it has the highest gravitational potential energy.
hope this helps
please mark it brainliest :D
EC_1 + EP_1 = EC2 + EP_2
EC_2 = 0
EC_2 = EP_1 - EP_2
EC_2 = mg(H_1 - H_2) = 0.20 kg * 9.8 m/s^2 * (3.25 m - 1.5m) = 3.43 J
Answer:5101.35v
Explanation:
Radius of gold nucleus=7.3×10-15m and a charge of +79e
Q= 79e
e=1.6×10^-19
q= +2e
The nucleus is considered as the point charge where the potential energy between the charges are
U = 1/(4×3.142×Eo)×(qQ)/r
Where r is distance between the charges and the nucleus
r=R+d
V=U/q
U= 1/(4×3.142×Eo)×Q/r
V= 1/(4×3.142×Eo)×Q/(r+d)
9.0×10^9 ×(79×10^-19)/(7.3×10^-15)+(1.5×10^-14)
V= 9.0×10^9 ×(1.264×10^-17)/(2.23×10^-14)
V= 9×10^9×(5.67×10^-14)= 5101.35v