Answer:
C
Step-by-step explanation:
According to SohCahToa, cosine is adjacent over the hypotenuse.
The adjacent when looking from angle b, is 21.
The hypotenuse of this triangle is 29.
So Cos B=21/29
The probability of obtaining two blue marbles without replacement is equal to 0.15.
We are given that:
The number of yellow marbles = 3
Number of red marbles = 9
Number of Blue marbles = 8
Total marbles = 3 + 9 + 8
Total marbles = 20
Now, we have to calculate the probability of obtaining two blue marbles without replacement.
The probability will be:
P( obtaining two blue marbles without replacement ) = 8 / 20 × 7 / 19
P( obtaining two blue marbles without replacement ) = 56 / 380
P( obtaining two blue marbles without replacement ) = 0.15
Therefore, the probability of obtaining two blue marbles without replacement is equal to 0.15.
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Answer:
105
Step-by-step explanation:
300 x 0.35 = 105
Answer:
nice
Step-by-step explanation:
Answer:
Below.
Step-by-step explanation:
f) (a + b)^3 - 4(a + b)^2
The (a+ b)^2 can be taken out to give:
= (a + b)^2(a + b - 4)
= (a + b)(a + b)(a + b - 4).
g) 3x(x - y) - 6(-x + y)
= 3x( x - y) + 6(x - y)
= (3x + 6)(x - y)
= 3(x + 2)(x - y).
h) (6a - 5b)(c - d) + (3a + 4b)(d - c)
= (6a - 5b)(c - d) + (-3a - 4b)(c - d)
= -(c - d)(6a - 5b)(3a + 4b).
i) -3d(-9a - 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b).
= (3d + 2c)(9a + 2b).
j) a^2b^3(2a + 1) - 6ab^2(-1 - 2a)
= a^2b^3(2a + 1) + 6ab^2(2a + 1)
= (2a + 1)( a^2b^3 + 6ab^2)
The GCF of a^2b^3 and 6ab^2 is ab^2, so we have:
(2a + 1)ab^2(ab + 6)
= ab^2(ab + 6)(2a + 1).
