A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.
1. 
Check:
The multiplicative inverse of 5 in 
is 9.
2. 
Check:
The multiplicative inverse of 5 in 
is 5.
3. 
Check:
The multiplicative inverse of 5 in 
is 8.
Merry Christmas and a happy new year
x is your starting running time. 1/10 of a minute is 6 seconds, so you can do x - 6(6). 6 times 6 = 36, so your answer is x - 36 seconds. 36 seconds.
Answer:
i). x³ + 9x² + yz - 15
ii). -21m³np - 8p⁵q + mnp + 4mn + 100
Step-by-step explanation:
Question (38)
i). Two expressions are -5x² - 4yz + 15 and x³+ 4x²- 3yz
By subtracting expression (1) from expression (2) we can the expression by addition which we can get expression (1).
(x³+ 4x²- 3yz) - (-5x² - 4yz + 15) = x³ + 4x² - 3yz + 5x² + 4yz - 15
= x³ + 9x² + yz - 15
ii). -15m³np + 2p⁵q - 6m³pn + mnp + 4mn - 10qp⁵+ 100
= (-15m³np - 6m³np) + (2p⁵q - 10qp⁵) + mnp + 4mn + 100
= -21m³np - 8p⁵q + mnp + 4mn + 100
SO what you need to do is:
<span>Start with |f(x) - 3| < 0.4
and plug in f(x) = x+1
to get
|f(x) – 3| < 0.4
|x+1 – 3| < 0.4
|x - 2| < 0.4
-0.4 < x - 2 < 0.4
-0.4+2 < x < 0.4+2
1.6 < x < 2.4
So delta would be 2.3
Hope this is what you were looking for
</span>
