Answer:
1. D
2. B
3. A
Step-by-step explanation:
Question 1:
The pair of <JKL and <LKM can be referred to as linear pairs. They are two adjacent angles that are formed from the intersecting of two lines.
Question 2:
Given that <KLM = x°
<KML = 50°
<JKL = (2x - 15)°
According to the exterior angle theorem, exterior ∠ JKL = <KLM + KML.
2x - 15 = x + 50
Solve for x
2x - x = 15 + 50
x = 65
Therefore, <KLM = 65°
QUESTION 3:
<JKL = 2x - 15
Plug in the value of x
<JKL = 2(65) - 15
= 130 - 15
<JKL = 115°
Answer:
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
the "-" sign can't be true, because that would have turned the whole graph of x² upside-down. but it is not.
so, we need a positive sign for the x term.
and the whole graph is shifted to the right. so the functional value of x of F(x) is now the same that happened "earlier" (for smaller x) with G(x). so, the argument "x" is now reduced (by 3 units, as the graph is shifted right by 3 units) in the calculation compared to the original G(x) calculation.
therefore, the ...(x-3)... expression is right.
so, positive sign and "(x-3)" is only in C.
