Answer:
3, 12, 27 and 300
Step-by-step explanation:
Plug n as 1, 2, 3 and 10.
3(1)² = 3
3(2)² = 12
3(3)² = 27
3(10)² = 300
Answer:
Step-by-step explanation:
They're asking for the initial fuel, which is how much it had when the distance was 0. so 500, your y-intercept
The probability that exactly 4 of the selected adults believe in reincarnation is 5.184%, and the probability that all of the selected adults believe in reincarnation is 7.776%.
Given that based on a poll, 60% of adults believe in reincarnation, to determine, assuming that 5 adults are randomly selected, what is the probability that exactly 4 of the selected adults believe in reincarnation, and what is the probability that all of the selected adults believe in reincarnation, the following calculations must be performed:
- 0.6 x 0.6 x 0.6 x 0.6 x 0.4 = X
- 0.36 x 0.36 x 0.4 = X
- 0.1296 x 0.4 = X
- 0.05184 = X
- 0.05184 x 100 = 5.184
- 0.6 x 0.6 x 0.6 x 0.6 x 0.6 = X
- 0.36 x 0.36 x 0.6 = X
- 0.1296 x 0.6 = X
- 0.07776 = X
- 0.07776 x 100 = 7.776
Therefore, the probability that exactly 4 of the selected adults believe in reincarnation is 5.184%, and the probability that all of the selected adults believe in reincarnation is 7.776%.
Learn more in brainly.com/question/795909
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Change the fraction into a decimal
