Since the acceleration of car is uniform so the distance traveled by car while brakes are applied is given by

given that



now plug in all data in above formula


so car will cover 14.4 m distance while it apply brakes
Answer:
<em>Force B</em>
Explanation:
<u>Friction Force
</u>
It's a force that appears when an object is tried to move on a rough surface. There are two cases: when the object is at rest, we have the friction static coefficient and when the object is already moving, we have the dynamic coefficient. The static coefficient is usually greater than the second because it's harder to overcome the friction when the object is at rest.
We are told that John pushes the bed to the left with enough force to overcome the force of friction. If the movement is intended to be to the left side, the friction force appears to the right, since it always opposes to the movement. Thus the force B is the one who represents the friction force in this situation
Up ward direction...
Positive direction
Answer:
they both evaperated bye heat
Explanation: