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2 years ago

The planet Venus, our moon, and Halley's Comet all

Physics

2 answers:

olganol [36]2 years ago

3 0

D is your answer <span>have highly predictable orbits around the sun. </span>

lapo4ka [179]2 years ago

3 0

Answer: The correct answer is Option D.

Explanation:

Venus is the second planet of our solar system and is similar in size as compared to Earth. It's atmosphere is mainly composed of carbon dioxide with minor amounts of nitrogen. This planet have a fixed orbital time around the sun which is 225 days.

Moon is the natural satellite of Earth and is smaller than Earth. It is composed of mainly oxygen, silicon, magnesium, iron, calcium, and aluminum. The orbital period of moon around Sun is 29.5 days.

Halley's Comet is a comet which is very small as compared to Earth and is composed of water, carbon monoxide, carbon dioxide and other ices. It appears in every 75-76 years.

Hence, all of the above have highly predictable orbits around the Sun. Therefore, the correct answer is Option D.

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2 years ago

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A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth. What multiple of Earth's radius RE g

7nadin3 [17]

Answer:

(a) r = 1.062·R $_E$ = $\frac{531}{500} R_E$

(b) r = $\frac{33}{25} R_E$

Explanation:

Here we have escape velocity v $_e$ given by

$v_e =\sqrt{\frac{2GM}{R_E} }$ and the maximum height given by

$\frac{1}{2} v^2-\frac{GM}{R_E} = -\frac{GM}{r}$

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v = $0.241\times \sqrt{\frac{2GM}{R_E} }$ so that;

v² = $0.058081\times {\frac{2GM}{R_E} }$

v² = ${\frac{0.116162\times GM}{R_E} }$

$\frac{1}{2} v^2-\frac{GM}{R_E} = -\frac{GM}{r}$ is then

$\frac{1}{2} {\frac{0.116162\times GM}{R_E} }-\frac{GM}{R_E} = -\frac{GM}{r}$

Which gives

$-\frac{0.941919}{R_E} = -\frac{1}{r}$ or

r = 1.062·R $_E$

(b) Here we have

$K_i = 0.241\times \frac{1}{2} \times m \times v_e^2 = 0.241\times \frac{1}{2} \times m \times \frac{2GM}{R_E} = \frac{0.241mGM}{R_E}$

Therefore we put $\frac{0.241GM}{R_E}$ in the maximum height equation to get

$\frac{0.241}{R_E} -\frac{1}{R_E} =-\frac{1}{r}$

From which we get

r = 1.32·R $_E$

ME = KE - PE

Where the KE = PE required to leave the earth we have

ME = KE - KE = 0

The least initial mechanical energy to leave the earth is zero.

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3 years ago

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Why do hot stars look bluer than cool stars?

brilliants [131]

Answer:

(B) The wavelength that a star radiates the most energy is inversely proportional to the temperature.

Explanation:

As we know that

According to Wien's law wavelength is inverse proportional to the temperature .

λ.T = Constant.

λ.∝ 1 /T

As we know that star radiates wavelength and this wavelength is inverse proportional to the temperature of the star.

The temperature of cool star is cooler than the temperature of hot star that is cool star looks red and hot star looks blue.Cool star have low energy and hot star have high energy.

So option B is correct.

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3 years ago

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natulia [17]

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2 years ago

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tresset_1 [31]

Answer:

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Explanation:

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