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Liula [17]
3 years ago
7

An object of mass m is attached to a vertically oriented spring. The object is pulled a short distance below its equilibrium pos

ition and released from rest. Set the origin of the coordinate system at the equilibrium position of the object and choose upward as the positive direction. Assume air resistance is so small that it can be ignored.
Physics
1 answer:
Airida [17]3 years ago
3 0

Answer:

The motion is described by a set of explanations below

Explanation:

For the part A, the position of the moment is represented by the plot on each side in the far left. Because the mass has been pulled down, this can only assume the negative downward direction. Thus, graphs D and H will be negative on the far left at a position when the time t = 0.

For the part B, the position of the mass will be at point E.

For the part C, the mass will be at the position F. This is because the acceleration is a derivative of the velocity of the object as given by the following derivative equation:

a = \frac{d}{dt}(v)

where a = acceleration and v is the velocity.

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After fixing a flat tire on a bicycle you give the wheel a spin. Its initial angular speed was 5.45 rad/s and it rotated 14.4 re
Komok [63]

Answer:

(a) α = -0.16 rad/s²

(b) t = 33.2 s

Explanation:

(a)

Applying 3rd equation of motion on the circular motion of the tire:

2αθ = ωf² - ωi²

where,

α = angular acceleration = ?

ωf = final angular velocity = 0 rad/s (tire finally stops)

ωi = initial angular velocity = 5.45 rad/s

θ = Angular Displacement = (14.4 rev)(2π rad/1 rev) = 28.8π rad

Therefore,

2(α)(28.8π rad) = (0 rad/s)² - (5.45 rad/s)²

α = -(29.7 rad²/s²)/(57.6π rad)

<u>α = -0.16 rad/s²</u>

<u>Negative sign shows deceleration</u>

<u></u>

(b)

Now, we apply 1st equation of motion:

ωf = ωi + αt

0 rad/s = 5.45 rad/s + (-0.16 rad/s²)t

t = (5.45 rad/s)/(0.16 rad/s²)

<u>t = 33.2 s</u>

6 0
3 years ago
A train travels 99 kilometers in 2 hours, and then 90 kilometers in 3 hours. What is its average speed?
Agata [3.3K]

Average speed =

(total distance)/(total time)

Average speed = (99+90)/(2+3)

That's (189 km) / (5 hr)

Average speed = 37.8 km/hr

3 0
2 years ago
When driving on roads that may be slippery: A. Always drive at the maximum speed limit. B. Use cruise control to maintain a stea
erik [133]

When driving on roads that may be slippery, do not make any sudden changes in speed or direction. Option D is correct.

<h3 /><h3>What is a slippery surface?</h3>

The slick road sign serves as a warning.  When the road is wet or ice, drivers should use extra caution and reduce their speed. When the weather is bad, avoid making any rapid changes in direction.

When driving on roads that may be slippery, do not make any sudden changes in speed or direction. It may cause accident because the vehicle can lose their balance.

Hence, option D is correct.

To learn more about the slippery surface, refer to the link;

brainly.com/question/1953680

#SPJ1

7 0
1 year ago
Please help me!!!!<br> Describe the roles these organisms play in their ecosystem.
creativ13 [48]

Answer:

Explanation:

Deer = primary consumer

Green plants = producer

Fungi = decomposers

3 0
3 years ago
A ride-sharing car moving along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed
fgiga [73]

Answer:

Explanation:

Time taken to accelerate to 28 m /s

= 28 / 2 = 14 s

a ) Total length of time in motion

= 14 + 41 + 5

= 60 s .

b )

Distance covered while accelerating

s = ut + 1/2 at²

= 0 + .5 x 2 x 14²

= 196 m .

Distance covered while moving in uniform motion

= 28 x 41

= 1148 m

distance covered while decelerating

v = u - at

0 = 28 - a x 5

a = 5.6 m / s²

v² = u² - 2 a s

0 = 28² - 2 x 5.6 x s

s = 28² / 2 x 5.6

= 70 m .

Total distance covered

= 196 + 1148 + 70

= 1414 m

total time taken = 60 s

average velocity

= 1414 / 60

= 23.56 m /s .

8 0
3 years ago
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