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Liula [17]
3 years ago
7

An object of mass m is attached to a vertically oriented spring. The object is pulled a short distance below its equilibrium pos

ition and released from rest. Set the origin of the coordinate system at the equilibrium position of the object and choose upward as the positive direction. Assume air resistance is so small that it can be ignored.
Physics
1 answer:
Airida [17]3 years ago
3 0

Answer:

The motion is described by a set of explanations below

Explanation:

For the part A, the position of the moment is represented by the plot on each side in the far left. Because the mass has been pulled down, this can only assume the negative downward direction. Thus, graphs D and H will be negative on the far left at a position when the time t = 0.

For the part B, the position of the mass will be at point E.

For the part C, the mass will be at the position F. This is because the acceleration is a derivative of the velocity of the object as given by the following derivative equation:

a = \frac{d}{dt}(v)

where a = acceleration and v is the velocity.

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If a body of mass 5og moves in a circular path of radius 10cm .find work done
Sindrei [870]

Answer:

0Nm, no work is done.

Explanation:

Work done is defined as the Force per distance meaning force times the distance moved in the direction of the force.

Now the body of mass 50g has a centripetal force acting on it directed towards the centre. Now in actuality the body stays along the circle it doesn't really move to the centre of the circle.

Hence the force doesn't move a distance, and so from the definition of work done;

F×d ; d =0

Hence work done = mv2/r × 0= 0Nm

3 0
3 years ago
I need help like right now!!!!! please
Mariana [72]

1. All of the above

2. Lack of consistent sunlight

3. Nonpolluting & Can be developed anywhere

4. Protons and Neutrons

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5 0
3 years ago
Why do high-altitude clouds tend to appear before a warm front arrives in a region?
Ilia_Sergeevich [38]

Answer:

Global Warming

Explanation:

That's why

8 0
3 years ago
Read 2 more answers
Plz help!
Strike441 [17]
72km/hr = 72000m/3600seconds(we convert km/hr to m/s
= 20m/s
Velocity= 20m/s
In 4seconds,distance covered=20x4= 80m
Therefore,an accident occurs because in 4seconds, the car would have moved past 20m
6 0
3 years ago
Unpolarized light with an average intensity of 845 W/m2 moves along the x-axis when it enters a Polarizer A with a vertical tran
horsena [70]

Answer:

θ = 36.2º

Explanation:

When light passes through a polarizer it becomes polarized and if it then passes through a second polarizer, it must comply with Malus's law

         I = I₀ cos² tea

The non-polarized light between the first polarized of this leaves half the intensity, with vertical polarization

          I₁ = I₀ / 2

          I₁ = 845/2

          I₁ = 422.5 W / m²

In this case, the incident light in the second polarizer has an intensity of I₁ = 422.5 W / m² and the light that passes through the polarizer has a value of

I = 275 W / m ²

      Cos² θ = I / I₁

      Cos θ = √ I / I₁

      Cos θ = √ (275 / 422.5)

     Cos θ = 0.80678

     θ = cos⁻¹ 0.80678

     θ = 36.2º

This is the angle between the two polarizers

8 0
3 years ago
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