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bekas [8.4K]
3 years ago
7

Solve this equation, x-5=11 (Please include step by step)

Mathematics
1 answer:
Andru [333]3 years ago
4 0
X-5=11
+5 both sides
x=16
hope this helped
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Look at the attachment for the work.

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3 years ago
What is the domain and range of the function y = 2x2 - 4x - 10?
11111nata11111 [884]

Answer:

Step-by-step explanation:

The domain of all polynomials is all real numbers.  To find the range, let's solve that quadratic for its vertex.  We will do this by completing the square.  To begin, set the quadratic equal to 0 and then move the -10 over by addition. The first rule is that the leading coefficient has to be a 1; ours is a 2 so we factor it out.  That gives us:

2(x^2-2x)=10

The second rule is to take half the linear term, square it, and add it to both sides.  Our linear term is 2 (from the -2x).  Half of 2 is 1, and 1 squared is 1.  So we add 1 into the parenthesis on the left.  BUT we cannot ignore the 2 sitting out front of the parenthesis.  It is a multiplier.  That means that we didn't just add in a 1, we added in a 2 * 1 = 2.  So we add 2 to the right as well, giving us now:

2(x^2-2x+1)=10+2

The reason we complete the square (other than as a means of factoring) is to get a quadratic into vertex form.  Completing the square gives us a perfect square binomial on the left.

x^2-2x+1=(x-1)^2 and on the right we will just add 10 and 2:

2(x-1)^2=12

Now we move the 12 back over by subtracting and set the quadratic back to equal y:

2(x-1)^2-12=y

From this vertex form we can see that the vertex of the parabola sits at (1,-12).  This tells us that the absolute lowest point of the parabola (since it is positive it opens upwards) is -12.  Therefore, the range is R={y|y ≥ -12}

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D

Step-by-step explanation:

8 0
2 years ago
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You move the decimal point forward until it reaches the one so it looks like this:

1.4 x 10⁵ 

the exponent, 5, just tells you how many spaces the decimal point moved.
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3 years ago
Explain the error in the work shown. Find the correct answer.
svetlana [45]

The bases were not the same when the exponents were set equal to each other.

16 should have been written as 4 squared.

The exponent on the right should be 4a instead of 8a.

The correct solution is a=-3/4.

3 0
3 years ago
Read 2 more answers
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