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jeyben [28]
3 years ago
10

A concentrated aqueous solution of Pb(NO3)2 is slowly added to 1.0 L of a mixed aqueous solution containing 0.010 M Na2CrO4 and

2.5 M NaBr in an attempt to selectively precipitate only one of the anions. The sparingly soluble salt that precipitates first (neglecting any volume change) is ________ with a [Pb2+] concentration of ________.
Ksp(PbCrO4) = 1.8 × 10–14, Ksp(PbBr2) = 6.3 × 10–6
Chemistry
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer:

This means the amount of PbCrO4 will precipitate first, with a [Pb^2+] concentration of 1.8*10^-12 M

Explanation:

Step 1: Data given

Molarity of Na2CrO4 = 0.010 M

Molarity of NaBr = 2.5 M

Ksp(PbCrO4) = 1.8 * 10^–14

Ksp(PbBr2) = 6.3 * 10^–6

Step 2: The balanced equation

PbCrO4 →Pb^2+ + CrO4^2-

PbBr2  → Pb^2+ + 2Br-

Step 3: Define Ksp

Ksp PbCrO4 = [Pb^2+]*[CrO4^2-]

1.8*10^-14 = [Pb^2+] * 0.010 M

[Pb^2+] = 1.8*10^-14 /0.010

[Pb^2+] = 1.8*10^-12 M

The minimum [Pb^2+] needed to precipitate PbCrO4 is 1.8*10^-12 M

Ksp PbBr2 = [Pb^2+][Br-]²

6.3 * 10^–6 = [Pb^2+] (2.5)²

[Pb^2+] = 1*10^-6 M

The minimum [Pb^2+] needed to precipitate PbBr2 is 1*10^-6 M

This means the amount of PbCrO4 will precipitate first, with a [Pb^2+] concentration of 1.8*10^-12 M

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The Prandtl number, Pr, is a dimensionless group important in heat transfer. It is defined as Pr - Cp*mu/k where Cp is the heat
algol [13]

Answer:

The Prandtl number for this example is 14,553.

Explanation:

The Prandlt number is defined as:

Pr=\frac{C_{p}*\mu}{k}

To compute the Prandlt number for this case, is best if we use the same units in every term of the formula.

\mu=1896 \frac{lbm}{ft*h}*\frac{1000 g}{2.205 lbm}*\frac{3.281 ft}{1 m}*\frac{1h}{3600s}  =7938 \frac{g}{m*s}

Now that we have coherent units, we can calculate Pr

Pr=\frac{C_{p}*\mu}{k}=0.66*7938/0.36=14553

8 0
3 years ago
A chemist dissolves 248mg of pure hydrochloric acid in enough water to make up 140mL of solution.Calculate the pH of the solutio
evablogger [386]

Answer : The pH of the solution is, 1.31

Explanation : Given,

Mass of HCl = 248 mg = 0.248 g      (1 mg = 0.001 g)

Volume of solution = 140 mL

Molar mass of HCl = 36.5 g/mole

First we have to calculate the concentration of hydrochloric acid.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }HCl\times 1000}{\text{Molar mass of }HCl\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{0.248g\times 1000}{36.5g/mole\times 140mL}=0.0485mole/L=0.0485M

The concentration of HCl is, 0.0485 M

As we know that, HCl dissociates to give hydrogen ion and chloride ion.

The dissociation reaction is:

HCl\rightarrow H^++Cl^-

Concentration of HCl = Concentration of H⁺ = Concentration of Cl⁻ = 0.0485 M

Now we have to calculate the pH of the solution.

pH : It is defined as the negative logarithm of hydrogen ion concentration.

Mathematically,

pH=-\log [H^+]

pH=-\log (0.0485)

pH=1.31

Therefore, the pH of the solution is, 1.31

6 0
2 years ago
2. Which type of glassware is used for general mixing, measuring and
ella [17]

Answer:

D

Explanation:

A beaker can be used for boiling coz it can withstand high temperatures.

It can be used for measuring the volume of a solid indirectly by measuring the displacement of a liquid.

It can as well be used for mixing coz it flat bottomed

5 0
2 years ago
Click the "draw structure" button to launch the drawing utility. Draw the product of the reaction of propanal with lithium alumi
WINSTONCH [101]

Answer:

Product: propan-1-ol

Explanation:

IIn this case, we have to remember that LiAlH_4  is a reduction agent.  So, this is a <u>reduction reaction</u>. The LiAlH_4 has the ability to produce <u>hydride ions </u>H^-. This ion can attack the <u>carbonyl group</u> generating a negative charge in the oxygen. In the next step, the negative charge in the oxygen can attack a water molecule to<u> protonate</u> the molecule and produce <u>propan-1-ol</u>.

See figure 1

I hope it helps!

8 0
3 years ago
Can someone explain how I would solve this?
ValentinkaMS [17]

Answer:

sorry I don't know about this yet

4 0
2 years ago
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