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drek231 [11]
3 years ago
15

Question is in the image

Chemistry
2 answers:
Bond [772]3 years ago
8 0

Answer:

C) 3

Explanation:

Al +  H2SO4 → Al2(SO4)3 + H2

2Al + H2SO4  → Al2(SO4)3 + H2

2Al + 3H2SO4 → Al2(SO4)3 + H2

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

zloy xaker [14]3 years ago
6 0

Answer:(3)

Explanation: 2Al+3H2SO4----->Al(2SO4)3+3H2

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What leads to the formation of gallstones?
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6832 J of heat energy is applied to 5.9 mol of water. If the original temperature of the water was 18.60C, the final temperature
sineoko [7]

Answer: The final temperature of the water will be 34.0^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=6832 Joules

m= mass of water = 5.9mol\times 18g/mol=106.2g

c = specific heat capacity = 4.184J/g^0C

Initial temperature of the water = T_i = 18.6^0C

Final temperature of the water = T_f  = ?

Putting in the values, we get:

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T_f=34.0^0C

The final temperature of the water will be 34.0^0C

8 0
3 years ago
Heat of fusion (?Hfus) is used for calculations involving a phase change between solid and liquid, with no temperature change. F
Butoxors [25]

Answer:

q = 38,5 kJ

Explanation:

In its melting point, at 0°C, water is liquid. The boiling point of water is 100°C. It is possible to estimate the heat you required to raise the temperature of water from 0°C to 100°C using:

q = C×m×ΔT

Where C is specific heat of water (4,184J/g°C), m is mass of water (92,0g) and ΔT is change in temperature (100°C-0°C = 100°C)

Replacing:

q = 4,184J/g°C×92,0g×100°C

q = 38493 J, in kilojoules:

<em>q = 38,5 kJ</em>

<em></em>

I hope it helps!

6 0
3 years ago
What happens to a liquid when you keep on cooling it until it changes?
Gnesinka [82]

Answer:

it turns into a solid

6 0
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