The coefficient of expansion is 13 * 10^-6 m per meter length.per oK
The temperature difference = 42 - - 8 = 50 oC
delta T = (42 + 273) - (-8 + 273) = 50 oK
delta L = L * 13* 10^6 m/oK
oK = 50 oK delta L = 19.5 cm = 19.5 cm [1m / 100 cm] = 0.195m
So we need to find the length and it is computed by:
0.195= L * 13 * 10^-6 * 50 L = 0.195 / (13*10^-6*50) L = 300 m
Answer:
The net force on the car is 2560 N.
Explanation:
According to work energy theorem, the amount of work done is equal to the change of kinetic energy by an object. If '
' be the work done on an object to change its kinetic energy from an initial value '
' to the final value '
', then mathematically,
where '
' is the mass of the object and '
' and '
' be the initial and final velocity of the object respectively. If '
' be the net force applied on the car, as per given problem, and '
' is the displacement occurs then we can write,
Given, 
.
Equating equations (I) and (II),
Answer:
Dance studio
Explanation:
Martial art use to defend ourself from any dangerous. Dance is a way to learn it
