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salantis [7]
3 years ago
7

Got some easy questions, to do. Will give, Branliest.:) ​

Mathematics
2 answers:
Ivanshal [37]3 years ago
8 0

1.)3

2.)6

3.)9

4.)12

5.)18

6.)?

7.)?

Goryan [66]3 years ago
6 0

Answer:

a = 27

b = 225

c = no

Step-by-step explanation:

a = 3 multiplied by 9

b = 3 multiplied by 75

c = understand the pattern, then imagine how will it look with 41 beads

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harry is 14 years old ,and larry is 7. how many times older is harry than larry? what is known and the unknown ​
allsm [11]

Answer:

Harry is 7 more years older then larry

Step-by-step explanation:

Harry is 7 more years older then larry because if you sutract 7-14 you get 7

3 0
3 years ago
Read 2 more answers
Find the domain of fg
vazorg [7]
We have the following functions:
 f (x) = x ^ 2 + 1
 g (x) = 1 / x
 Multiplying we have:
 (f * g) (x) = (x ^ 2 + 1) * (1 / x)
 Rewriting:
 (f * g) (x) = ((x ^ 2 + 1) / x)
 Therefore, the domain of the function is given by all the values of x that do not make zero the denominator.
 We have then:
 All reals except number 0
 Answer:
 
b. all real numbers, except 0
7 0
4 years ago
Read 2 more answers
Marcelo can select from 2 types of oranges and 3 types of peaches. If he randomly selects 1 orange and 1 peach, how many possibl
ICE Princess25 [194]
6

2x3=6

oranges-
peaches-

possible combination:
1-

2-

3-

4-

5-

6-
8 0
3 years ago
An automobile assembly line runs for 9 3/4 hours each day. employees work 3/4 hours shift. how many shifts are there in each day
babunello [35]

Answer:

the mixed fraction 9 3/4 means there are 9 4/4 s and one 3/4all togather there are 39/4 divid this by 3/4 to find the no of shifts. 39/4 ÷(3/4)

=39/4. ×4/3=13

13shifts

4 0
3 years ago
A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece
Alex_Xolod [135]

Answer:

The number of seat when n is odd S_n=\frac{n^2+2n+1}{4}

The number of seat when n is even S_n=\frac{n^2+2n}{4}

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

S_n=\frac{n}{2}[2a+(n-1)d]

    =\frac{n}{2}[a+l]

a = first term of the series.

d= common difference.

n= number of term

l= last term

n^{th} term of a A.P series is

T_n=a+(n-1)d

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let t^{th} of the series is n.

T_n=a+(n-1)d

Here T_n=n, n=t, a=1 and d=2

n=1+(t-1)2

⇒(t-1)2=n-1

\Rightarrow t-1=\frac{n-1}{2}

\Rightarrow t = \frac{n-1}{2}+1

\Rightarrow t = \frac{n-1+2}{2}

\Rightarrow t = \frac{n+1}{2}

Last term l= n,, the number of term =\frac{ n+1}2, First term = 1

Total number of seat

S_n=\frac{\frac{n+1}{2}}{2}[1+n}]

    =\frac{{n+1}}{4}[1+n}]

     =\frac{(1+n)^2}{4}

    =\frac{n^2+2n+1}{4}

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let t^{th} of the series is n.

T_n=a+(n-1)d

Here T_n=n, n=t, a=2 and d=2

n=2+(t-1)2

⇒(t-1)2=n-2

\Rightarrow t-1=\frac{n-2}{2}

\Rightarrow t = \frac{n-2}{2}+1

\Rightarrow t = \frac{n-2+2}{2}

\Rightarrow t = \frac{n}{2}

Last term l= n, the number of term =\frac n2, First term = 2

Total number of seat

S_n=\frac{\frac{n}{2}}{2}[2+n}]

    =\frac{{n}}{4}[2+n}]

     =\frac{n(2+n)}{4}

    =\frac{n^2+2n}{4}  

4 0
3 years ago
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