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kumpel [21]
3 years ago
7

Find the length of the line segment shown below.

Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

Answer:

The end points of line segment are:

(x_1,y_1) = (5,4)\\(x_2,y_2)  = (-4,-3)

Using distance formula,

Distance = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}} = \sqrt{(-4-5)^{2}+(-3-4)^{2}} = \sqrt{(-9)^{2}+(-7)^{2}} = \sqrt{81+49}=\sqrt{130} units

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Jose and Maris work for different car dealerships. Jose earns a monthly salary of $3,500 plus a 6% commission on his sales, x. M
aev [14]

Answer: d.3,500 + 0.06x > 4,000 + 0.04x

Step-by-step explanation:

Hi, to answer this question we have to write each inequality:

Jose earns a monthly salary of $3,500 plus a 6% commission on his sales, x.

So, his monthly earnings must be equal to the sum of the fixed monthly salary ($3500) plus the product of the number of sales (x) and the commission percentage in decimal form (divided by 100):

So:

Jose’s earnings: 3,500 + x (6/100)

Jose’s earnings: 3,500 + 0.06x

Maris earns a monthly salary of $4,000 plus a 4% commission on her sales.

So, her monthly earnings must be equal to the sum of the fixed monthly salary ($4000) plus the product of the number of sales (x) and the commission percentage in decimal form (divided by 100):

Maris’ earnings: 4000+ x (4/100)

Maris’ earnings: 4000+ 0.04 x

Since Jose's earnings must be greater than Maris' earnings

3,500 + 0.06x >4000+ 0.04 x

4 0
3 years ago
Find the exact length of the curve. y2 = 4(x + 1)3, 0 ≤ x ≤ 1, y > 0
mylen [45]
We can find this using the formula: L= ∫√1+ (y')² dx

First we want to solve for y by taking the 1/2 power of both sides:

y=(4(x+1)³)^1/2
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Now, we can take the derivative using the chain rule:

y'=3(x+1)^1/2

We can then square this, so it can be plugged directly into the formula:

(y')²=(3√x+1)²
<span>(y')²=9(x+1)
</span>(y')²=9x+9

We can then plug this into the formula:

L= ∫√1+9x+9 dx *I can't type in the bounds directly on the integral, but the upper bound is 1 and the lower bound is 0
L= ∫(9x+10)^1/2 dx *use u-substitution to solve
L= ∫u^1/2 (du/9)
L= 1/9 ∫u^1/2 du
L= 1/9[(2/3)u^3/2]
L= 2/27 [(9x+10)^3/2] *upper bound is 1 and lower bound is 0
L= 2/27 [19^3/2-10^3/2]
L= 2/27 [√6859 - √1000]
L=3.792318765

The length of the curve is 2/27 [√6859 - √1000] or <span>3.792318765 </span>units.
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3 years ago
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Answer:

The answer is

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Answer:

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