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vovangra [49]
2 years ago
14

The number of particles of 0.2 mole​

Chemistry
1 answer:
strojnjashka [21]2 years ago
3 0

Answer:

There are 1.205x10²³ particles in 0.2 moles.

Explanation:

In order to <u>convert from moles to number of particles</u> we need to use <em>Avogadro's number</em>, which states the number of particles contained in 1 mol:

  • 0.2 mol * 6.023x10²³ particles /mol = 1.205x10²³ particles

Thus, there are 1.205x10²³ particles in 0.2 moles.

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A. 35Cl1-

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Chlorine needs 1 more electron to have full octet thus will take 1 electron and possess a -1 charge.

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Describe in your own words, in terms of particle movement and energy, what occurs when a liquid is cooled to its freezing point.
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Calculate the solubility (in mol/L) of Fe(OH)3 (Ksp = 4.0 x 10^-38) in each of the following situations:
netineya [11]

Answer:

(A) 1.962x10^-10 M solubility in pure water

(B) 4.0 x 10^-33 M solubility

(C) 4.0 x 10^-27 M solubility

Explanation:

(A) Fe(OH)3 would give (Fe3+) and (3OH-)

Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

Let y = [Fe^3+]

Let 3y = [OH-]

4x10^-38 = (y)(3y)^3

4x10^-38 = 27y^4

y^4 = 4x10^-38 ÷ 27

y^4 = 1.481 x 10^-39

y = 1.962x10^-10 M solubility in pure water

(B) pH = 5.0

5.0 = - log [OH-]

-5.0 = log [OH-]

[OH-] = 10^-5.0 =  1.0 x 10^-5 M

So, Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

[Fe^3+][1.0 x 10^-5] = 4.0 x 10^-38

[Fe^3+] = 4.0 x 10^-38 ÷ 1.0 x 10^-5

= 4.0 x 10^-33 M solubility

(C) pH = 11.0

11.0 = - log [OH-]

-11.0 = log [OH-]

[OH-] = 10^-11.0 =  1.0 x 10^-11 M

So, Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

[Fe^3+][1.0 x 10^-11] = 4.0 x 10^-38

[Fe^3+] = 4.0 x 10^-38 ÷ 1.0 x 10^-11

= 4.0 x 10^-27 M solubility

6 0
3 years ago
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