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liq [111]
3 years ago
9

Iv'e got a long one

Chemistry
1 answer:
EleoNora [17]3 years ago
7 0

1.) A

2.) C

3.) A

4.) A

5.) C

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NH3 +<br>H2SO4 → __(NH4)2SO4​
Zielflug [23.3K]

Answer:

This is not a balanced equation

Explanation:

Let's make it a balanced equation.

2 NH3 + H2So4 = (NH4)2So4

Glad I could help!!

8 0
3 years ago
Marissa is learning about the unique properties of waves. She has learned that whenever the wavelength of a wave increases, the
Goshia [24]

Answer:

I believe it is B

Explanation:

4 0
3 years ago
c. The reaction Br2 (l) --&gt; Br2 (g) has ΔH = 30.91 kJ/mol and ΔS = 93.3 J/mol·K. Use this information to show (within close a
egoroff_w [7]

Answer:

The answer to your question is given below.

Explanation:

From the question given above, the following data were obtained:

Br₂ (l) —> Br₂(g)

Enthalpy change (ΔH) = 30.91 KJ/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

Next, we shall convert 30.91 KJ/mol to J/mol. This can be obtained as follow:

1 KJ/mol = 1000 J/mol

Therefore,

30.91 KJ/mol = 30.91 × 1000

30.91 KJ/mol = 30910 J/mol

Thus, 30.91 KJ/mol is equivalent to 30910 J/mol.

Finally, we shall determine the boiling temperature of bromine. This can be obtained as follow:

Enthalpy change (ΔH) = 30910 J/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

ΔS = ΔH / T

93.3 = 30910 / T

Cross multiply

93.3 × T = 30910

Divide both side by 93.3

T = 30910 / 93.3

T = 331.29 K

Thus, the boiling temperature of bromine is 331.29 K

6 0
3 years ago
A solution is created by dissolving 13.0 grams of ammonium chloride in enough water to make 295 mL of solution. How many moles o
Masja [62]

Answer:

(a) Moles of ammonium chloride = 0.243 moles

(b) Molarity_{ammonium\ chloride}=0.824\ M

(c) 60.68 mL

Explanation:

(a) Mass of ammonium chloride = 13.0 g

Molar mass of ammonium chloride = 53.491 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{13.0\ g}{53.491\ g/mol}

<u>Moles of ammonium chloride = 0.243 moles</u>

(b) Moles of ammonium chloride = 0.243 moles

Volume = 295 mL = 0.295 L ( 1 mL = 0.001 L)

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity_{ammonium\ chloride}=\frac{0.243}{0.295}

Molarity_{ammonium\ chloride}=0.824\ M

(c) Moles of ammonium chloride = 0.0500 moles

Volume = ?

Molarity = 0.824 M

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

0.824\ M=\frac{0.0500}{Volume}

<u>Volume = 0.05 / 0.824 L = 0.06068 L = 60.68 mL</u>

6 0
3 years ago
A temperature inversion can cause a warm air mass to move over a colder air mass. This traps the colder air mass and prevents
Zina [86]
I would have to say the answer is A) SMOG.
5 0
3 years ago
Read 2 more answers
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