(a) 764.4 N
The weight of the astronaut on Earth is given by:
where
m is the astronaut's mass
g is the acceleration due to gravity
Here we have
m = 78.0 kg
g = 9.8 m/s^2 at the Earth's surface
So the weight of the astronaut is
(b) 21.1 N
The spacecraft is located at a distance of
from the center of Earth.
The acceleration due to gravity at a generic distance r from the Earth's center is
where G is the gravitational constant and M is the Earth's mass.
We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:
(1)
the acceleration due to gravity at r=6R instead will be
And substituting (1) into this formula,
So the weight of the astronaut at the spacecratf location is
Answer:
The displacement is zero miles
Explanation:
The displacement of an object that moves from point A to point B is defined as
Where d is the displacement of the object. The displacement does not depend on the trajectory of the object. It only depends on the linear distance between the end point and the starting point.
In this case we know that the person walks from home to work and then walks from work to home. Therefore, the total displacement is the linear distance between the point where its journey begins and the point where the route ends.
The tour begins on the front porch of your house and ends on the front porch of your house (when you return from work). If we call A to the front porch of the house then the displacement is:
The displacement is zero miles, since the person finishes the journey just where it started (front porch)
Is an imbalance of electric charges within or on the surface of a material.
Explanation:
Spring tides generally occur twice a month—during new and full moons, when the Earth, Sun, and Moon line up in a row. In this arrangement, the gravities of the Sun and Moon work together and have the strongest pull on Earth. This produces the largest difference between high and low tide.
Spring Tides
During full moon or new moon phases, the gravitational forces of the Sun and Moon are maximized, producing very large ranges of tidal highs and lows called spring tides
Answer:
t = 1.62 s
Explanation:
given,
mass of the block m₁ = 16.5 Kg
m₂ = 8 Kg
angle of inclination = 60°
μs = 0.400 and μk = 0.300
time to slide 2 m = ?
a) let a is the acceleration of the block m₁ downward.
Net force acting on m₂,
F₂ = T - m₂ g
m₂a = T - m₂ g
.......(1)
net force acting on m₁
F₁ = m₁g sin(60°) - μ_k m₁g cos (60°) - T
m₁ a = m₁g sin(60°) - μ_k m₁g cos (60°) - T
.........(2)
from equations 1 and 2
T = 90.61 N
from equation (1)
.......(1)
a = 1.52 m/s²
let t is the time taken
Apply,
d = ut + 0.5 a t²
2 = 0 + 0.5 x 1.52 x t²
t = 1.62 s
