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cluponka [151]
3 years ago
14

Two identical tiny spheres of mass m =2g and charge q hang from a non-conducting strings, each of length L = 10cm. At equilibriu

m, each string makes and angle θ =50 with the vertical. Find the size of the charge on each spere.

Physics
1 answer:
garri49 [273]3 years ago
8 0

Answer:

q = 7.88μC

Explanation:

In the diagram attached, you can visualize the situation. Separation distance between the 2 charges is:

D = 2*L*sin θ = 0.1532m

From a sum of forces on the X-axis:

T*sin \theta = Fe

And on the y-axis:

T*cos \theta = m*g   Solving for T and replacing its value on the X-axis equation we get:

m*g*tan \theta = Fe  Since Fe = \frac{K*q^2}{D^2}

m*g*tan \theta = \frac{K*q^2}{D^2}  Solving for q we get:

q = 7.88μC

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