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Helen [10]
3 years ago
7

a ball dropped from rest falls freely intil it hits the ground with the speed of 20 m/s . the tine furing which the ball is in f

ree fall is approximately
Physics
1 answer:
forsale [732]3 years ago
4 0

Answer:

5m/s

Explanation:

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A piece of curved glass has a radius of curvature of r = 10.8 m and is used to form Newton's rings, as in the drawing. Not count
MAVERICK [17]

Answer:

Radius of the outer most dark fringe is 2.65 cm

Solution:

As per the question:

Radius of curvature of the glass, r = 10.8 m

No. of dark fringes, n = 100

Wavelength of light, \lambda = 652\ nm = 652\times 10^{- 9}\ m

Now,

To calculate the radius R of the outermost ring:

Radius of the dark fringe of nth order is given by:

R^{2} = nr\lambda = 100\times 10.8\times 652\times 10^{- 9} = 7.042\times 10^{- 4}

R = \sqrt{7.042\times 10^{- 4}} = 0.0265\ m = 2.65\ cm

7 0
4 years ago
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1.) A neutron in a reactor makes an elastic
alisha [4.7K]

Answer:

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Explanation:

7 0
2 years ago
A branch of mechanics dealing with the mathematical methods of describing motion
alexdok [17]
Kinematics is the branch of Physics that deals with
the mathematical methods of describing motion.
3 0
4 years ago
What is the acceleration of a car that travels in a straight line?
Sphinxa [80]
Acceleration occurs when there is a change in speed or direction. If it travels in a straight line, there is no speed or change in direction as it is constant througout, hence 0 acceleration.

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6 0
3 years ago
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Find the velocity (in m/s) of a proton that has a momentum of 4.96 X 10^-19 kg.m/s.
kramer

Answer:

The velocity of the proton is 2.965*10^{8} \frac{m}{s}

Explanation:

The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:

p=m*v Equation (1)

Where:

p: Is the momentum in kg*m/s

m: Is mass of the particle in kg

v: Is the velocity of the particle in m/s

Data known:

m= 1,6726 × 10^–27 kg : mass of the proton

p= 4.96 X 10^-19 kg.m/s.

We replace this data in the Equation (1):

4,96*10^{-19} =1.6726*10^{-27} *vv=\frac{4.9*10^{-19} }{1.6726*10^{-27} }

v=(\frac{4.96}{1.6726} )*(10^{27-19} )

v=2,965*10^{8} m/s

Answer: The velocity of the proton is 2.965*10^{8} \frac{m}{s}

3 0
3 years ago
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