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jek_recluse [69]
3 years ago
12

A 4-kW resistance heater in a water heater runs for 3 hours to raise the water temperature to the desired level. Determine the a

mount of electric energy used in both kWh and kJ.
Physics
1 answer:
neonofarm [45]3 years ago
7 0

Answer:

12kWhr

Explanation:

Energy = Power * Time

Power = 4kW

Time = 3hrs

Substitute into the formula

Energy used up = 4kW * 3hrs

Energy used up = 12kWhr

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Clothes dryer uses about 3:00 amps of current from a 240-volt line how much power does it use
kirill115 [55]

Electrical power is defined as

P = I * V

I = 3 amperes

V = 240 volts

Power = 3 * 240

Power = 720 Watts. Answer

4 0
3 years ago
If a ball is thrown straight up into the air with an initial velocity of 40 ft/s, it height in feet after t second is given by y
Tasya [4]
We should first calculate the highest point that ball reaches. 
y' = 40 - 32t = 0
t = 40/32 = 1,25s
y = 25 feet.

To calculate average velocity we use simple formula:
Vav=s/t   where s is traveled distance by the time t.



for t=2  we calculate y
y = 16
(i)  for t = 2,5     y = 0
Vav = 16/0.5 = 32 feet/s
(ii) for t = 2.1     y = 13.44
Vav = 2.56/0.1 = 25.6 feet/s
(iii) for t = 2.01  y = 15.7584
Vav = 0.2416/0.01= 24.16 feet/s

it seems like the answer would be 24 feet/s. There is a way to calculate that.
5 0
3 years ago
Two stars in a faraway part of the Milky Way are orbiting each other as a binary star system. By
natita [175]

Answer: M_{total}= 1.85

Explanation: Estimate the total mass of a binary system is done by a reformulation of <em>Kepler's Third Law</em>, which states that the square of the period of a planet's orbit is proportional to the cube of its semimajor axis, i.e.:

a^{3}=(M_{1}+M_{2})P^{2}

where

a is semimajor axis in astronomical units (AU);

P is period measured in years;

M_{1}+M_{2} is total mass of the two-stars system;

For the two stars faraway in the Milky Way:

1 year is equivalent of 365 days, so period in years:

P=\frac{594}{365}

P = 1.63 years

Calculating total mass:

a^{3}=(M_{total})P^{2}

M_{total}=\frac{a^{3}}{P^{2}}

M_{total}=\frac{1.7^{3}}{1.63^{2}}

M_{total}= 1.85

<u>The total mass of the two-object system is 1.85 mass units.</u>

3 0
4 years ago
When an electron de-excites from the third quantum level to the second, and then to the ground state, two photons are emitted. T
Leokris [45]

Answer:

ground state

Explanation:

  Lets take  

n=3 ,n=2 ,n=1 are the energy level.

Energy level n=1 is the ground energy level.

The energy from 3 to 1 = hν

The energy from 3 to 2 = hν₁

The energy from 2 to 1 = hν₂

We can say that

hν = hν₁ +  hν₂

If the electron were de-excitation from the third level to ground level then the sum of emitted frequency will be equal to the frequency of a single electron.

Therefore the answer is ground state.

3 0
3 years ago
Cindy rides her bike
Cloud [144]

Answer:

its 30 i did this homeweok

Explanation:

30

3 0
3 years ago
Read 2 more answers
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