Answer: The magnetic field is 4×10^-4T
Explanation:
Using the magnetic field equation
B=μI/2πr
B= magnetic field =?
l= current in the wire=2.0A
r= distance from the axis of wire=1.0mm= 0.001m
μ=magnetic permeability =4π×10^-7N/m
B= (4π×10^-7 × 2.0)/(2π × 0.001)
B= 4×10^-4T
Therefore the magnetic field is 4×10^-4T
Answer:
792 J
Explanation:
The total energy of the ball is E = U + K where U = potential energy = mgh and K = kinetic energy = 1/2mv²
E = mgh + 1/2mv² where m = mass of ball = 2.0 kg, g = acceleration due to gravity = 9.8 m/s², h = height of building = 20.0 m, v = initial velocity of ball = 20.0 m/s.
So, substituting the values of the variables into E, we have
E = mgh + 1/2mv²
= 2.00 kg × 9.8 m/s² × 20.0 m + 1/2 × 2.00 kg × (20.0 m/s)²
= 392 J + 400 J
= 792 J
Answer:
A downward force of magnitude 5 N is exerted on the book by the force of ... Do the downward force in Part A (gravity) and the upward force in Part B ...
Answer:
The speed of the shell at launch and 5.4 s after the launch is 13.38 m/s it is moving towards the Earth.
Explanation:
Let u is the initial speed of the launch. Using first equation of motion as :
a=-g
The velocity of the shell at launch and 5.4 s after the launch is given by :
So, the speed of the shell at launch and 5.4 s after the launch is 13.38 m/s it is moving towards the Earth.