Answer:
What is 2^-3 x 3^-2 as a fraction?
What is (-2)^-3 x (-3)^-2 as a fraction
Explanation:
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Answer:
The magnitude of the force is 1.29*10^-3N in the positive x direction
Explanation:
In order to calculate the magnitude and direction of the force, you take into account that the force is the space derivative of the potential enrgy, as follow:
(1)
where:

You replace the expression for U into the equation (1) and solve for F:
(2)
The force on the particle, for x = -0.080m is:

The magnitude of the force is 1.29*10^-3N in the positive x direction
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The speed he was moving at when he finished falling is 30 m/s.
The given parameters;
mass of the bungee, m = 80 kg
impulse provided by the rope, J = 3200 Ns
initial upward velocity of the jumper, u = 10 m/s
- Let the final velocity after falling = v
- Let the upwards motion = negative
- Let the downwards motion when falling = positive
Apply the principle of conservation of linear momentum;
J = ΔP = Δmv = m(v - u)
3200 = 80(v - (-10))
3200 = 80(v + 10)

Thus, the speed he was moving at when he finished falling is 30 m/s.
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The answer is D. If you aren't consistent with your drop positions, then your data may be invalid. To be frank: it basically screws over the experiment.