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Sergeu [11.5K]
3 years ago
13

Define the following and give an example of each:_______.

Chemistry
1 answer:
Ber [7]3 years ago
6 0
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h2>\huge\textbf{Van de Waal}</h2>

London Dispersion force or Van de Waals force is a temporary attractive force which are the weakest and occur between nonpolar noble gases and same charges. This force is weaker because they have more electrons that are farther from the nucleus and are able to move around easier.

Example: N_2, F_2, \ I_2

<h2>_____________________________________</h2>

\huge\textbf{Dipole - Dipole Forces}

Dipole force is present between the polar molecules. Polar molecules are those molecules which have slightly negative and slightly positive charge. Dipole-dipole forces are attractive forces between the positive end of one polar molecule and the negative end of another polar molecule.

Example: HCl, HF, CHCl_3

<h2>_____________________________________</h2>

\huge\textbf{Hydrogen Bonding}

It is a special type of dipole force present between polar molecules, it is formed between Hydrogen atom which forms positive ion, and the other negative ion. It results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom. The hydrogen bond is one of the strongest intermolecular attractions, but weaker than a covalent or an ionic bond.

Example: Every polar molecule which has hydrogen has hydrogen bonding i.e. H_2O, NH_3

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h2 />
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1.which of the following correctly describes carbon, represented by c?
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A 52 gram sample of an unknown metal requires 714 Joules of energy to heat it from
ratelena [41]

Answer:  Approximately 0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}

===================================================

Work Shown:

We have the following variables

  • Q = 714 joules = heat required
  • m = 52 grams = mass
  • c = specific heat = unknown
  • \Delta t = 82-30.5 = 51.5 = change in temperature

note: the symbol \Delta is the uppercase Greek letter delta. It represents the difference or change in a value.

Apply those values into the formula below. Solve for c.

Q = m*c*\Delta t\\\\714 = 52*c*51.5\\\\714 = 52*51.5*c\\\\714 = 2678*c\\\\2678*c = 714\\\\c = \frac{714}{2678}\\\\c \approx 0.26661687826737\\\\c \approx 0.267\\\\

The specific heat of the unknown metal is roughly 0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}

3 0
3 years ago
How many grams of glucose are needed to form 150g of ethanol?
Svetradugi [14.3K]
<span>1 mole glucose gives 2 moles of ethanol

moles of glucose in 2.4 kg = 2400 / 180.18 = 13.320 moles

so moles of ethanol produced = 2* 13.32 = 26.64 moles

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6 0
4 years ago
Determine how many gmol, kmol, and lbmols there are in 50 kilograms of n-hexane.
Artist 52 [7]

Answer: 581 gmol

0.581 kmol

1.28\times 10^{-3}lbmol

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{50\times 1000g}{86g/mol}=581mol

1. The conversion for mol to gmol

1 mol = 1 gmol

581 mol= \frac{1}{1}\times 581=581gmol

2. The conversion for mol to kmol

1 mol = 0.001 kmol

581 mol= \frac{0.001}{1}\times 581=0.581kmol

3. The conversion for mol to lbmol

1 mol = 2.2\times 10^{-3}lbmol

581 mol= \frac{2.2\times 10^{-3}}{1}\times 581=1.28\times 10^{-3}lbmol

3 0
3 years ago
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