Answer:
no effect
Explanation:
In an SN2 reaction, the mechanism is bi-molecular and first order in both the alkyl halide and the nucleophile.
Hence the rate of reaction is;
Rate = k [1-iodo-2-methylbutane] [cyanide ion]
Given that it is a bimolecular reaction, if we double the concentration of 1-iodo-2-methylbutane and the concentration of the cyanide ion is halved, the rate of reaction remains the same.
Answer:
6.286 L.
Explanation:
Applying Charles Law,
V/T = V'/T'............................... Equation 1
Where V = Initial volume of the balloon, T = Initial Temperature of the balloon, V' = Final volume of the balloon, T' = Final Temperature of the balloon
make V' the subject of the equation
V' = VT'/T............................ Equation 2
Given: V = 6.50 L, T = 31 °C = (273+31) K = 304 K, T' = 21 °C = (273+21) K = 294 K
Substitute into equation 2
V' = 6.5(294)/304
V' = 6.286 L.
Hence the new volume in the balloon = 6.286 L.
Answer:
0.0984mol of F2
Explanation:
The equation for the reaction is given below:
Kr + F2 → KrF2
Let us convert 12g of KrF2 to mole. This is illustrated below
Molar Mass of KrF2 = 84 + (2x19) = 84 + 38 = 122g/mol
Mass of KrF2 = 12g
Number of mole = Mass /Molar Mass
Number of mole of KrF2 = 12/122 = 0.0984mol
From the equation,
1mole of F2 produced 1mole of KrF2.
Therefore 0.0984mol of F2 will produce 0.0984mol of KrF2
3028 molucoles bro it’s lit
