Answer:
537.68 torr.
Explanation:
- We can use the general law of ideal gas:<em> PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and V are constant, and have different values of P and T:
<em>(P₁T₂) = (P₂T₁).</em>
P₁ = 485 torr, T₁ = 40°C + 273 = 313 K,
P₂ = ??? torr, T₂ = 74°C + 273 = 347 K.
∴ P₂ = (P₁T₂)/(P₁) = (485 torr)(347 K)/(313 K) = 537.68 torr.
1) Data:
<span>initial decay rate, No =16,800 disintegrations/min
final decay rate, Nf = 10,860 disintegrations/min
t = 28.0 days
t half-life =?
2) Formulas
Radioactive disintegration =>
Nt = No * e ^ (-kt)
t half-life = ln (2) / k
3) Solution
From Nt = No * e^ (-kt) =>
Nt / No = e ^ (-kt)
=> -kt = ln (Nt / No)
=> kt = ln (No/Nt)
=> k = ln (No / Nt) / t
=> k = ln (16,800 / 10,860) / 28 days = 0.01558 days^ -1
From t half-life = ln(2) / k
t half-life = ln(2) / (0.01558 days^-1) = 44.5 days.
Answer: 44.5 days.
</span>
Answer:
24.45 L
Explanation:
From General gas equation,
PV/T = P'V'/T'.................... Equation 1
Where P = initial pressure, V = Initial volume, T = Initial Temperature, P' = Final pressure, V' = Final Volume, T' = Final Temperature.
make V' the subject of the equation.
V' = PVT'/(TP')................. Equation 2
Given: P = 760 torr, V = 22.4 L, T = 0 °C = (0+273) = 273 K, T' = 25 °C = (25 + 273) = 298 K, P' = 760 torr
Substitute into equation 2
V' = 760(22.4)(298)/(760×273)
V' = 24.45 L.
Hence the volume of the gas = 24.45 L
Answer:
B. kilogram
Explanation:
The basic SI unit of mass is the kilogram.
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