Answer is: 22,65 gramsof methanol <span>must be burned.
</span>Chemical reaction: CH₃OH + 3/2O₂ → CO₂ + 2H₂O. ΔH = -764 kJ.
Make proportion, if one mole of ethanol release 764 kJ of heat, than:
1 mol : 764 kJ = n(CH₃OH) : 541 kJ.
n(CH₃OH) = 0,708 mol.
m(CH₃OH) = n(CH₃OH) · M(CH₃OH).
m(CH₃OH) = 0,708 mol · 32 g/mol.
m(CH₃OH) = 22,65 g.
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