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Sphinxa [80]
3 years ago
6

What is the part of the neuron that receives information from other neurons, muscles, or glands

Chemistry
1 answer:
Sliva [168]3 years ago
5 0
The answer is dendrites. Dendrites extend from the neuron cell body and receive messages from other neurons. Synapses are the contact points where one neuron communicates with another. The dendrites are covered with synapses formed by the ends of axons from other neurons.
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Why is it possible to use physical properties to separate a mixture
morpeh [17]
To get the exact measurement
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Name the form of carbon used for absorbing poisonous gases and purification of noble gases​
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Activated carbon, also called activated charcoal, is a form of carbon processed to have small, low-volume pores that increase the surface area available for adsorption or chemical reactions.
7 0
3 years ago
Consider the chemical reaction represented by the equation below:
svlad2 [7]

3 MgCl2 + 2 Al = 3 Mg + 2 AlCl3

Since we know that we have 12 moles of MgCl2 and enough Al, we don't need to figure out the exact amount of Al.

3 MgCl2 / 2 AlCl3  =  12 mol MgCl2 / x mol AlCl2

cross-multiply

3 MgCl2(x mol AlCl2)  =  12 mol MgCl2(2 AlCl3)

3x = 24

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8 moles AlCl3

Alternatively, we know that we have 12 moles of MgCl2, and a coefficient of 3. This indicates a multiplier of 4 for the entire equation, meaning 2 AlCl3 multiplied by (4) = 8 moles

6 0
3 years ago
Write a net ionic equation for the reaction that occurs when nickel(II) sulfide and excess hydrochloric acid (aq) are combined.
kondaur [170]

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8 0
3 years ago
1.00 mole of oxygen at 60 degrees celcius and 5 bar is flowing through a 20cm diameter pipe (inner diameter). What is the veloci
jeka94

Answer:

u = 0.176 m/x

Explanation:

∴ n O2 = 1 mol

∴ mass O2 = 1 mol * 32 g/mol = 32 g

∴ T = 60°C = 333 K

∴ P = 5 bar

⇒ V = RTn/P = (83.14 bar.cm³/mol.K)*(333 K)*(1 mol))/(5 bar)

⇒ V = 5537.124 cm³

∴ d = 20cm

⇒ A = (1/4π)*d² = 314.16 cm²

velocity of the gas (m/x):

  • u = m / ρ*A
  • let time (t) = x sec

∴ ρ = 32 g / 5537.124 cm³ = 5.78 E-3 g/cm³

∴ mass flow rate (m) = 32g / x

⇒ u = (32 g/x) / (( 5.78 E-3 g/cm³)*(314.16cm²))

⇒ u = 17.625 cm/x * ( m/100cm) = 0.176 m/x

4 0
3 years ago
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