Answer:
um.. is this a quiz or what girl...
First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2
Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
Answer:
the answer is C
Explanation:
6.7 to 13.2 then look at the numbers they go up but not a lot each time
Answer:
c. HF can participate in hydrogen bonding.
Explanation:
<u>The boiling points of substances often reflect the strength of the </u><u>intermolecular forces</u><u> operating among the molecules.</u>
If it takes more energy to separate molecules of HF than of the rest of the hydrogen halides because HF molecules are held together by stronger intermolecular forces, then the boiling point of HF will be higher than that of all the hydrogen halides.
A particularly strong type of intermolecular attraction is called the hydrogen bond, <em>which is a special type of dipole-dipole interaction between the hydrogen atom in a polar bond</em>, such as N-H, O-H, or F-H, and an electronegative O, N, or F atom.
Answer:
New volume V2 = 120.4 ml
Explanation:
Given:
Pressure P1 = 1.12 atm
New pressure P2 = 1.12[1+0.25] = 1.4 atm
Old volume V1 = 150.5 ml
Find:
New volume V2
Computation:
P1V1 = P2V2
(1.12)(150.5) = (1.4)(V2)
V2 = 120.4 ml
New volume V2 = 120.4 ml