3 years ago

How many extraneous solutions does the equation below have?

Mathematics

1 answer:

yawa3891 [41]3 years ago

3 0

Answer:

Two extraneous solutions

Step-by-step explanation:

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Vesnalui [34]

Answer:

Option B. $x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$14x^{2}+9x+10=0$

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substitute in the formula

$x=\frac{-9(+/-)\sqrt{9^{2}-4(14)(10)}} {2(14)}$

$x=\frac{-9(+/-)\sqrt{-479}} {28}$

Remember that

$i=\sqrt{-1}$

substitute

$x=\frac{-9(+/-)\sqrt{479}i} {28}$

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Answer:

Step-by-step explanation:

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