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3 years ago

Please help I will mark brainliest

Mathematics

2 answers:

nevsk [136]3 years ago

7 0

C. 3.50 W

Hope this helps you out with your homework!

Sveta_85 [38]3 years ago

5 0

Answer: C

Step-by-step explanation:

$3.50/lb is the unit weight. Since your # of lbs is x it would be 3.50x. Simple

Have a nice day :)

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Which shows all the exact solutions of sin^2 x + 3cos x - 1 = 2?

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Answer:

x = 2k $\pi$ is the solution of this equation.

Step-by-step explanation:

This question is related to trigonometric equations.

The given equation is,

$sin^{2} x + 3cos x - 1 = 2$

We have to find the solutions of this equation.

Put $sin^{2}x = 1 - cos^{2}x$

$1 - cos^{2}x$ + 3cosx - 1 = 2

$cos^{2}x -3cosx+2$ = 0

For this equation only cosx = 1 is possible solution.

Cosx = 1 happens when x is a multiple of 2 $\pi$

So x = 2k $\pi$ is the solution of this equation.

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3 years ago

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An item is regularly priced at $30. It is on sale for 20% off the regular price. How much in dollars) is discounted from the regular price?

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3 years ago

Find m and n if if the sum of zeros of mx²-2x + n is 4, and product is 4

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Step-by-step explanation:

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3 years ago

A certain type of automobile battery is known to last an average of 1140 days with a standard deviation of 80 days. If 400 of th

Sever21 [200]

Answer:

Mean = $\mu = 1140$

Standard deviation = $\sigma = 80$

Find the probabilities for the average length of life of the selected batteries.

A)The average is between 1128 and 1140.

We are supposed to fidn P(1128<x<1140)

Formula : $Z=\frac{x-\mu}{\sigma}$

At x = 1128

$Z=\frac{1128-1140}{80}$

$Z=-0.15$

Refer the z table for p value

P(x<1128)=0.4404

At x = 1140

$Z=\frac{1140-1140}{80}$

$Z=0$

Refer the z table for p value

P(x<1140)=0.5

So,P(1128<x<1140)=P(x<1140)-P(x<1128)=0.5-0.4404=0.0596

Hence the probabilities for the average length of life of the selected batteries is between 1128 and 1140 is 0.0596

B)The average is greater than 1152.

P(x>1152)

At x = 1128

$Z=\frac{1152-1140}{80}$

$Z=0.15$

Refer the z table for p value

P(x<1152)=0.5596

So,P(x>1152)=1-P(x<1152)=1-0.5596=0.4404

Hence the probabilities for the average length of life of the selected batteries is greater than 1152 is 0.4404

C) The average is less than 940.

P(x<940)

At x = 940

$Z=\frac{940-1140}{80}$

$Z=-2.5$

Refer the z table for p value

P(x<940)=0.5596

Hence the probabilities for the average length of life of the selected batteries is less than 940 is 0.5596

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3 years ago

Simplify negative 5 and 1 over 6 − negative 8 and 1 over 2

Tomtit [17]

Answer:

Hi there!

Your answer is;

17/6 OR 2 & 5/6

Step-by-step explanation:

(-5+1)/6 - (-8+1)/2

First, simplify in parentheses!

-4/6 - -7/2

Next, change the symbol of 7/2 because two negatives make a positive!

-4/6 +7/2

Next, change the denominators so they both have the same

-4/6 + 7/2

× 3/3

-4/6 + 21/6

Simplify!

17/6

OR

2 & 5/6

Hope this helps

4 0

3 years ago