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Tom [10]
3 years ago
8

A(n) 131 g ball is dropped from a height

Physics
1 answer:
larisa [96]3 years ago
7 0

Answer:

26.59 N/m

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 131 g

Extention (e) = 4.82755 cm

Acceleration due to gravity (g) = 9.8 m/s²

Spring constant (K) =?

Next, we shall convert 131 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

131 g = 131 g × 1 Kg / 1000 g

131 g = 0.131 Kg

Thus, 131 g is equivalent to 0.131 Kg.

Next, we shall the force exerted by the ball on the spring. This can be obtained as follow:

Mass (m) = 0.131 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = ma

F = 0.131 × 9.8

F = 1.2838 N

Next, we shall convert 4.82755 cm to metre (m)

This can be obtained as follow:

100 cm = 1 m

Therefore,

4.82755 cm = 4.82755 cm × 1 m / 100 cm

4.82755 cm = 0.0482755 m

Thus, 4.82755 cm is equivalent to 0.0482755 m

Finally, we shall determine the spring constant as follow:

Force (F) = 1.2838 N

Extention (e) = 0.0482755 m

Spring constant (K) =?

F = Ke

1.2838 = K × 0.0482755

Divide both side by 0.0482755

K = 1.2838 / 0.0482755

K = 26.59 N/m

Thus the spring constant is 26.59 N/m

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Explanation:

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<em> </em>

These two forces should be the same as the action force, which causes the locomotive to move up the hill if the velocity of the locomotive remains constant.          

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a body builder uses a chest expander with 5 strings.it takes a force of 200n to pull one string by 15cm.how much force will be n
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Complete Question:

Two identical soccer balls are rolled toward each other. What will be true after they collide headon?

Group of answer choices.

A. they will both stop rolling immediately after they collide head–on.

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C. They will both roll back at the same speed they had before the collision

D.They will both roll to the side at a faster speed after the collision

Answer:

C. They will both roll back at the same speed they had before the collision

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Newton's Third Law of Motion which states that, for every action there is an equal but opposite reaction.

This ultimately implies that, in every interaction, there is a pair of forces acting on the two interacting objects.

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Answer:

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Now,

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\Delta L = \frac{200\times 0.01}{4\times \pi 0.006^{2}\times 2.6\times 10^{6}} = 1.7\times 10^{- 3}\ m = 1.7\ mm

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