Answer:
The acceleration is in the same direction as the net force.
Explanation:
to find the magnitude of the net force, giving you 102 N. Use the magnitude of the force and the mass to find the magnitude of the acceleration: a = F/m = (102 N)/(100 kg) = 1.0 m/s2.
Answer:
The potential energy of a 2 kg mass at a height of 40 meters is 784 J
Explanation:
Potential energy is that energy that a body possesses due to the height at which it is located and whose unit of measurement of the International System of Units is the joule (J).
The potential energy of a body is the result of multiplying its mass by its height and by gravity:
Ep=m*g*h
Potential energy Ep, is measured in joules (J), mass m is measured in kilograms (kg), gravity, g, in meters / second-squared (
), and height, h , in meters (m).
In this case:
- Ep=?
- m= 2 kg
- g= 9.8
![\frac{m}{s^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
- h= 40 m
Replacing:
Ep= 2 kg* 9.8
* 40 m
Solving:
Ep= 784 J
<u><em>The potential energy of a 2 kg mass at a height of 40 meters is 784 J</em></u>
Answer:
![624\:\mathrm{m}](https://tex.z-dn.net/?f=624%5C%3A%5Cmathrm%7Bm%7D)
Explanation:
We can use kinematics equation
.
What we're given:
of 100.0 m/s
of 12 s
of -8.0
Solving for
:
![\Delta x=100\cdot 12+\frac{1}{2}\cdot -8\cdot 12^2=\boxed{624\:\mathrm{m}}](https://tex.z-dn.net/?f=%5CDelta%20x%3D100%5Ccdot%2012%2B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20-8%5Ccdot%2012%5E2%3D%5Cboxed%7B624%5C%3A%5Cmathrm%7Bm%7D%7D)
Answer:
ω' = 2.5 rad/s
Explanation:
mass of cockroach, m = 4 kg
mass of disk, M = 6 kg
Radius of disc= R
initial angular velocity, ω = 2 rad/s
Let the final angular velocity is ω'
As no external torque is applied, so the angular momentum is constant.
Angular momentum = Moment of inertia x angular velocity
I ω = I' ω'
![\frac{1}{2}\left ( M+m \right )R^{2}\times {2} = \left (\frac{1}{2}MR^{2}+m(0.5R)^{2}) \right )\omega '](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cleft%20%28%20M%2Bm%20%5Cright%20%29R%5E%7B2%7D%5Ctimes%20%7B2%7D%20%3D%20%5Cleft%20%28%5Cfrac%7B1%7D%7B2%7DMR%5E%7B2%7D%2Bm%280.5R%29%5E%7B2%7D%29%20%20%5Cright%20%29%5Comega%20%27)
![10R^{2} = 4R^{2}\omega '](https://tex.z-dn.net/?f=10R%5E%7B2%7D%20%3D%204R%5E%7B2%7D%5Comega%20%27)
ω' = 2.5 rad/s