1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tamiku [17]
3 years ago
15

A disoriented physics professor drives 3.25 km north, then 2.20 km west, and then 1.50 km south. Find the magnitude and directio

n of the resultant displacement, using the method of components. In a vector-addition diagram (roughly to scale), show that the resultant displacement found from your diagram is in qualitative agreement with the result you obtained by using the method of components

Physics
1 answer:
Nana76 [90]3 years ago
4 0

Answer: magnitude of resultant = 2.811km, direction of resultant = 209.6°

Explanation: The vector ( in this case displacement) that lies on the y axis is 3.25km north and 1.50km due south.

Their resultant is gotten below

Magnitude of resultant = 3.25 - 1.50 = 1.75km

Direction of resultant = north (direction of the bigger vector)

2.20km is the only vector acting on the x axis due east, combining this vector with the resultant of the vectors above, we realize that 2.2km west is perpendicular to 1.75km due north. Since 1.75km us due north, it implies that it is the vector on the positive y axis (vy) and 2.20km due west implies that it is the vector on the negative x axis(vx), thus their resultant is gotten using phythagoras theorem.

R = √ vx² + vy²

R = √ 2.20² + 1.75²

R = √ 7.9025

R= 2.1811km.

θ = tan^-1 (vy/vx)

θ = tan ^-1 (1.25/2.20)

θ = tan ^-1 (0.5618)

θ = 29.6°.

The direction of the vector is south west which implies the third quadrant of the trigonometric quadrant which implies 180 + θ

Thus the direction of the vector is 180 + 29.60 = 209.6°

From the picture attached to this answer we can see roughly that the magnitude of resultant is longer than it component and the vector is placed on the 3rd quadrant which verifies our quantitative claim.

You might be interested in
A car is accelerating to the right. In which direction is the applied force?
Natasha_Volkova [10]

Answer:

Left

Explanation:

The force is applied opposite of the acceleration.

8 0
3 years ago
A family pool holds 10,000 gallons of water how many cubic meters is this
ruslelena [56]
4959167 is how many cubic meters in 10,000 gallons of water
3 0
3 years ago
Read 2 more answers
Which elements are metalloids
zhannawk [14.2K]

The six commonly recognised metalloids are boron, silicon, germanium, arsenic, antimony, and tellurium....

7 0
3 years ago
A photon of wavelength 7.33 pm scatters at an angle of 157° from an initially stationary, unbound electron. What is the de Brogl
Ann [662]

Answer:

4.63 p.m.

Explanation:

The problem given here can be solved by the Compton effect which is expressed as

\lambda^{'}-\lambda=\frac{h}{m_e c}(1-cos\theta)

here, \lambda  is the initial photon wavelength, \lambda^{'} is the scattered photon wavelength, h is he Planck's constant, m_e is the free electron mass, c is the velocity of light, \theta  is the angle of scattering.

Given that, the scattering angle is, \theta=157^{\circ}

Putting the respective values, we get

\lambda^{'}-\lambda=\frac{6.626\times 10^{-34} }{9.11\times 10^{-31}\times 3\times 10^{8}  } (1-cos157^\circ ) m\\\lambda^{'}-\lambda=2.42\times 10^{-12} (1-cos157^\circ ) m\\\lambda^{'}-\lambda=2.42(1-cos157^\circ ) p.m.

Therfore,

\lambda^{'}-\lambda=4.64 p.m.

Here, the photon's incident wavelength is \lamda=7.33pm

So,

\lambda^{'}=7.33+4.64=11.97 p.m

From the conservation of momentum,

\vec{P_\lambda}=\vec{P_{\lambda^{'}}}+\vec{P_e}

here, \vec{P_\lambda} is the initial photon momentum, \vec{P_{\lambda^{'}}} is the final photon momentum and \vec{P_e} is the scattered electron momentum.

Expanding the vector sum, we get

P^2_{e}=P^2_{\lambda}+P^2_{\lambda^{'}}-2P_\lambda P_{\lambda^{'}}cos\theta

Now expressing the momentum in terms of De-Broglie wavelength

P=h/\lambda and putting it in the above equation we get,

\lambda_{e}=\frac{\lambda \lambda^{'}}{\sqrt{\lambda^{2}+\lambda^{2}_{'}-2\lambda \lambda^{'} cos\theta}}

Therfore,

\lambda_{e}=\frac{7.33\times 11.97}{\sqrt{7.33^{2}+11.97^{2}-2\times 7.33\times 11.97\times cos157^\circ }} p.m.\\\lambda_{e}=\frac{87.7401}{18.935} = 4.63 p.m.

This is the de Broglie wavelength of the electron after scattering.

8 0
3 years ago
EDGE 2021 WILL GIVE BRAINLIEST
defon

Answer:

B A new compound is formed

8 0
3 years ago
Other questions:
  • "An empty cylindrical barrel is open at one end and rolls without slipping straight down a hill. The barrel has a mass of 19.0 k
    15·1 answer
  • Which two energy sources can help a star maintain its internal thermal pressure? which two energy sources can help a star mainta
    7·2 answers
  • A coach wants her team to have fun, win some games, and be a productive unit. What is the most important personality trait the c
    8·2 answers
  • In a system, when energy is transformed from one form to another
    13·2 answers
  • A 72.9 kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of
    10·1 answer
  • What is meant by the term fitness​
    6·1 answer
  • The height of a cone is increasing at a rate of 10 cm/sec and its radius is decreasing so that its volume remains constant. How
    5·1 answer
  • I have a device that can generate sounds with frequencies between 800 Hz and 1600 Hz. I also have an unlabeled tuning fork that
    9·1 answer
  • Water displacement is used to find what?<br><br><br><br>a. volume <br><br><br><br>b. density ​
    11·1 answer
  • A sphere moves in simple harmonic motion with a frequency of 4.40 Hz and an amplitude of 3.50 cm. (a) Through what total distanc
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!