All categories

3 years ago

Write a program in C++ to swap two variables usingfunctions?

Computers and Technology

1 answer:

lilavasa [31]3 years ago

8 0

Answer:

#include <iostream>

using namespace std;

void swap(int& m, int& n) /* passing by reference so that changes will be made in the original values.*/

{

int t=m;

m=n;

n=t;

}

int main()

{

int val1,val2;

cout<<"Enter the values"<<endl;

cin>>val1>>val2;

cout<<"Values before swap "<<val1<<" "<<val2<<endl;

swap(val1,val2); //calling the function swap..

cout<<"Values after swap "<<val1<<" "<<val2<<endl;

return 0;

}

Explanation:

Created a function swap with 2 arguments m and n passed by reference.

You might be interested in

Matlab In this assignment you will write a function that will calculate parallel resistance for up to 10 parallel resistors. Cal

Ket [755]

Answer:

The complete Matlab code along with step by step explanation is provided below.

Matlab Code:

function Req=ParallelR(Number)

Number=input('Please enter the number of resistors: ');

if Number>10 | Number<=0

disp('Invalid input')

return

end

R=0;

for i=1:Number

r=input('Please enter the value of resistor: ');

R=R+1/r;

end

Req=1/R;

end

Explanation:

Parallel resistance is given by

$\frac{1}{Req} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}}...+\frac{1}{R_{N}}$

First we get the input from the user for how many parallel resistors he want to calculate the resistance.

Then we check whether the user has entered correct number of resistors or not that is from 1 to 10 inclusive.

Then we run a for loop to get the resistance values of individual resistors.

Then we calculated the parallel resistance and keep on adding the resistance for N number of resistors.

Output:

Test 1:

Please enter the number of resistors: 3

Please enter the value of resistor: 10

Please enter the value of resistor: 20

Please enter the value of resistor: 30

ans = 60/11

Test 2:

Please enter the number of resistors: 11

Invalid input

Test 3:

Please enter the number of resistors: 0

Invalid input

8 0

3 years ago

What is the difference between the paste and paste special options

Darina [25.2K]

Paste special allows the item being transferred to be formatted in several different ways. Paste is just going to be transferred the exact way you copied it.

7 0

3 years ago

How is the United Kingdom planning to use driverless cars beginning in 2015?

AlekseyPX

You need answers to the question

8 0

3 years ago

Read 2 more answers

Whereas < is called a relational operator, x < y is called a(n) ________. A) Arithmetic operator B) Relative operator C) R

Westkost [7]

Answer:

The answer is "Option C".

Explanation:

Relational expression are one or more variable and maybe even values, which operators have linked together. It is also known as the process, which is used to calculate the outcome, that is generated by the relational expression. These words are typically designed to answer the questions in boolean values, and other options were not correct, that can be described as follows:

In option A, This process is used to perform the mathematical operation, that's why it is not correct.
Option B and Option D both is used to compare values, that's why it is not correct.

3 0

4 years ago

Subtract (100000)2 from (111)2 using 1s and 2s complement method of subtraction

GenaCL600 [577]

Answer:

-11001

Explanation:

The following steps are performed in order to perform subtraction of the given binary numbers:

Step 1:

Find 2’s complement of the subtrahend. The subtrahend here is 100000

100000

First take 1's complement of 100000

1's complement is taken by inverting 100000

1's complement of 100000 = 011111

Now takes 2's complement by adding 1 to the result of 1's complement:

011111 + 1 = 100000

2's complement of 100000 = 100000

Step 2:

Add the 2's complement of the subtrahend to the minuend.

The number of bits in the minuend is less than that of subtrahend. Make the number of bits in the minuend equal to that of subtrahend by placing 0s in before minuend. So the minuend 111 becomes:

000111

Now add the 2's complement of 100000 to 000111

0 0 0 1 1 1

1 0 0 1 1 1

The result of the addition is :

1 0 0 1 1 1

Step 3:

Since there is no carry over the next step is to take 2's complement of the sum and place negative sign with the result as the result is negative.

sum = 1 0 0 1 1 1

2's complement of sum:

First take 1's complement of 1 0 0 1 1 1

1's complement is taken by inverting 1 0 0 1 1 1

1's complement of 1 0 0 1 1 1 = 0 1 1 0 0 0

Now takes 2's complement by adding 1 to the result of 1's complement:

0 1 1 0 0 0 + 1 = 0 1 1 0 0 1

Now place the minus sign with the result of 2's complement:

- 0 1 1 0 0 1

Hence the subtraction of two binary numbers (100000)₂ and (111)₂ is

(-011001)₂

This can also be written as:

(-11001)₂

6 0

3 years ago