Answer:
B. Remains constant throughout the flight
Explanation:
If we completely neglect air resistance then the projectile will not have any horizontal resistances to deal with, therefore the horizontal component will remain constant throughout the flight. This would continue to be the case until it meets some form of resistance. Which assuming that everything else is normal would be the case since the force of gravity will push the projectile down (vertical component) until it hits the ground which in that instance would act as an opposing force to the horizontal component as well.
Population density = Number of beetles / Unit Square Area
= 20 beetles / 5m² = 4 beetles per m²
Answer:
a)
The magnitude of the attractive force is 
b)
The magnitude of the repulsive force is 
c)
The magnitude of the net force is 
Explanation:
The explanation is shown on the first and second uploaded image
As the resistance of a circuit increases, the current will decreases.
<h3>What is ohm’s law?</h3>
Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
When all physical parameters and temperature are constant,
Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.
This current-voltage connection may be expressed mathematically by Ohm's law as;
V=IR
If the voltage is constant, the resistance of the circuit will be inversely proportional to the current.
Hence,as the resistance of a circuit increases, the current will decreases.
To learn more of the ohm's law, refer to the link;
brainly.com/question/796939
#SPJ4
Answer:
This delay affect conversations in the sense that recipient will be receive the message just 2.56 seconds after the message was sent.
Explanation:
The laser pulse has an ondulatory nature as electromagnetic wave, which can travel in the void. Speed of light is constant and distance between Earth and the Moon is:
This delay affect conversations in the sense that recipient will be receive the message just 2.56 seconds after the message was sent.
