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castortr0y [4]
3 years ago
5

An electron-dot structure is a convenient method of representing

Chemistry
1 answer:
kherson [118]3 years ago
8 0

Answer:

all electrons of the atom

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What is a polyprotic buffer?
coldgirl [10]
Buffers - mixtures of conjugate acid and conjugate base at ±1 pH unit from pH = pKa. Resistant to changes in pH in response to small additions of H+ or OH-. ... Polyprotic acids - dissociation of each H+ can be treated separately if the pKa values are different
3 0
3 years ago
9. Which statement provides evidence that supports the Big Bang Theory?* 2 points
liberstina [14]

The statement the chemical makeup of the universe has changed dramatically provides evidence that supports the Big Bang Theory (Option D).

<h3>What is the Big Bang Theory?</h3>

The Big Bang Theory is a widely accepted theory in physics that states all the universe began with a huge explosion and form then matters expanded in space at the same time that it is cooling.

Therefore, with this data, we can see that the Big Bang Theory states that the chemical composition of the universe associated with hydrogen and helium modified since this explosion.

Learn more about the Big Bang Theory here:

brainly.com/question/1973038

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4 0
10 months ago
Read 2 more answers
7.895 g + 3.4 g round to the correct number significant figures
DIA [1.3K]

Answer:

11.3 g

Explanation:

7.895 + 3.4 = 11.295

When rounded to correct number of significant figures --> 11.3

There are 3 significant figures in 11.3

7 0
2 years ago
A certain sample of a liquid has a mass of 42 grams and a volume of 35 centimeters3. What is the density of the liquid? The dens
Xelga [282]

Density of liquid= \frac{mass of liquid}{volume of liquid}.

so, density of liquid= \frac{42 gm}{35 cm^{3} }= 1.2 gm/cm³.

8 0
2 years ago
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A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?
Nastasia [14]

Answer:

At -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

                                          \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively.

           V_{1}  and V_{2} are initial and final volume respectively.

           T_{1} and T_{2} are initial and final temperature in kelvin scale respectively.

Here P_{1}=150.0kPa , V_{1}=1.75L , T_{1}=(273-23)K=250K, P_{2}=210.0kPa and V_{2}=1.30L

Hence    T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}

            \Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}

            \Rightarrow T_{2}=260K

            \Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}

So at -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

5 0
3 years ago
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