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lara31 [8.8K]
2 years ago
7

When heated, KClO3 decomposes into KCl and O2. If this reaction produced 88.4 g of KCl, how much O2 was produced (in grams)? 2KC

lO_3--->2KCl+3O_2. A) 2(KClO_3)=245.096 B) 2KCl=149.102g C) 3O_2=95.995
Chemistry
1 answer:
adoni [48]2 years ago
5 0
<span>Mass of KCl=          88.4g 
</span>Molar mass of KCl=39+35.5 
<span>                                =74.5 
</span><span> The Moles of KCl= 88.4/74.5
</span>                            =1.186
<span>If for  the 2 moles of KCl there are 3 moles of oxygen
</span>so

<span>1 mole of KCl will  give=3/2=1.5 moles of oxygen 
</span>
<span>1.186 moles of KCl will give =1.5*1.186=1.779 oxygen
</span><span>32 the molar mass of oxygen
</span>so its mass will be
<span>1.779 *32=56.928
</span>enjoy
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Step 1: Write out the formula to be used:

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Explanation:

Step 1: Given data

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