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Oksanka [162]
3 years ago
11

gAn optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is from the

slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be
Physics
1 answer:
igomit [66]3 years ago
7 0

Answer:

d = 68.5 x 10⁻⁶ m = 68.5 μm

Explanation:

The complete question is as follows:

An optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is  1.70m from the slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be?

The answer can be given by using the formula derived from Young's Double Slit Experiment:

y = \frac{\lambda L}{d}\\\\d  =\frac{\lambda L}{y}\\\\

where,

d = slit separation = ?

λ = wavelength = 633 nm = 6.33 x 10⁻⁷ m

L = distance from screen (detector) = 1.7 m

y = distance between bright fringes = 15.7 mm = 0.0157 m

Therefore,

d = \frac{(6.33\ x\ 10^{-7}\ m)(1.7\ m)}{0.0157\ m}\\\\

<u>d = 68.5 x 10⁻⁶ m = 68.5 μm</u>

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Explanation:

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1. What is the kinetic energy of a 1.75 kg ball travelling at a speed of 54 m/s?
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Answer:

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Kinetic Energy (K.E) can be determined using the formula

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now substituting m = 1.75, and v = 54 in the formula

K.E=\frac{1}{2}mv^2

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