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GenaCL600 [577]
3 years ago
9

A good alternative to sit ups is A. Crunches B. Leg Raises C. Side Twists

Physics
1 answer:
astraxan [27]3 years ago
6 0
It would probably be B
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The momentum of a 3000 kg truck is 6.36 x 104 kg·m/s. At what speed is the truck traveling? m/s
Harlamova29_29 [7]

Answer:

21.2m/s

Explanation

Given data

P=6.36 x 10⁴kg·m/s.

M=3000kg

From the momentum expression

P=mv

v=p/m

Substitute

v=63600/3000

v=21.2m/s

Hence the Velocity is 21.2m/s

6 0
3 years ago
Derivative of arcsin(cos(2x))<br> is this chain rule?
sergejj [24]
Yes, you need to use the chain rule. Also you need to use the derivative of arcsin which is in tables.

Derivative of y = arcsin(x) = 1 / [√(1 - x^2)]

Chain rule: Derivative of archsin(cos(2x)) =

y' = 1 / [√(1 - (cos(2x))^2)] *  derivative (cos(2x) =

y' = 1 / [√(1 - (cos(2x))^2)] * (- sin (2x)) * 2

y' = -2(sin(2x)) / [√( 1 - (cos(2x))^2]



8 0
3 years ago
the temperature of a bowl of hot soup goes down after the soup is poured into a bowl. whats happening to the motion of the parti
Stels [109]

Given what we know, as with all substances, the particles in the bowl of hot soup will slow down as they cool after being poured.

<h3>Why do particles slow when cooled?</h3>
  • This has to do with energy.
  • The soup particles are excited by heat energy.
  • As the soup is poured, its heat energy radiates and it loses energy.
  • Decreased energy causes the particles to slow down.

Therefore, the motion of the particles of the soup decrease or slows down as the soup cools due to the loss of energy they are experiencing. The soup radiates heat energy into the room or plate, causing the particles to lose energy and slow down.

To learn more about heat energy visit:

brainly.com/question/1495272?referrer=searchResults

6 0
3 years ago
Express the number in scientific notation: -8,675,300.0
stich3 [128]

Answer:

It would be -8.6753 x 10 to the 6th power

Explanation

4 0
3 years ago
A 14.0 m uniform ladder weighing 490 N rests against a frictionless wall. The ladder makes a 63.0°-angle with the horizontal.
crimeas [40]

Answer:

Explanation:

Given:

length of ladder r_L = 14m

weight of ladder F_L = 490N

position of firefighter r_F = 3.8m

weight of firefighter F_F = 820N

angle of ladder \alpha = 63

Unknown:

force of the wall on the ladder F_W

force of friction on base of ladder F_R

normal force on base of ladder F_N

From the free body diagram of the sketch you get 3 equations:

F_x = ma_x = F_W - F_R = 0\\ F_y = ma_y = F_N - F_F - F_L = 0\\ \tau _P = \overrightarrow{r} \times \overrightarrow{F} = r_FF_Fcos\alpha + \frac{1}{2}r_LF_Lcos\alpha - r_LF_Wsin\alpha = 0

Solving the equations gives:

F_W = F_R\\ F_N = F_F + F_L\\ F_W = \frac{r_FF_F + 0.5r_LF_L}{r_L tan\alpha}

a)

F_R = 238N\\ F_N = 1310N

b)

F_R = \mu F_N\\ \mu = \frac{F_R}{F_N} \\ \mu = 0.3

c) Using the result from b and solving for r_F

\\ \mu = 0.15\\ F_R = \mu F_N\\ r_F = 2.4m

4 0
3 years ago
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