Answer:
<em>The force that would be applied on the rope just to start moving the wagon is 122 N</em>
Explanation:
Frictional force opposes motion between two surfaces in contact. It is the force that must be applied before a body starts to move. Static friction opposes the motion of two bodies that are in contact but are not moving. The magnitude of static friction to overcome for the body to move can be calculated using equation 1.
F = μ x mg .............................. 1
where F is the frictional force;
μ is the coefficient of friction ( μs, in this case, static friction);
m is mass of the object and;
g is the acceleration due to gravity( a constant equal to 9.81 m/
)
from the equation we are provide with;
μs = 0.25
m = 50 kg
g = 9.81 m/
F =?
Using equation 1
F = 0.25 x 50 kg x 9.81 m/
F = 122.63 N
<em>Therefore a force of 122 N must be applied to the rope just to start the wagon.</em>
Explanation:
Assuming no air resistance, the horizontal acceleration at all points is 0, and the vertical acceleration at all points is -g (if near the surface of the Earth, -9.8 m/s²).
New Zealand hornworts and general information on them. ... in the top of the plant and remain attached to it and continue to grow throughout its life. ... are that the spaces between the cells are filled with mucilage rather then air chambers
Answer:
The acceleration towards the center will be 
Explanation:
Given the running track is an oval shape, and the diameter of each half-circle is 74 meters.
Also, the runner took 1 minute and 40 seconds to complete 400 m one round of the track.
We need to find the acceleration towards the center.
First, we will find the speed.
Where 
is the speed.
is the distance covered by the rider that is 400 meters.
is the time taken by the rider to complete the lap which is 1 minute and 40 seconds. 
seconds.
So,
And
Where 
is the acceleration towards the center.
is the radius which will be the half of the diameter 74 meters.
Hence, the radius will be 37 meters.
So, the centripetal acceleration of the rider will be
