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2 years ago

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Two teams are playing tug of war. Team A pulls to the right with a force of 450 N. Team B pulls to the left with a force of 415

N. What is the net force on the rope, and what is its direction? 35 N to the right 35 N to the left 865 N to the right 865 N to the left

1 answer:

motikmotik2 years ago

6 0

Answer:

35 N to the right.

Explanation:

450 is going to the right so you subtract what is going against it. Which gives you 35. And because 450 is bigger than 415, it'll be going to the right.

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Answer:

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Explanation:

Given that,

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$v_{x}=u\cos\theta$

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$v_{y}=u\sin\theta-gt$

Put the value into the formula

$v_{y}=20\sin40-9.8\times3.25$

$v_{y}=-19\ m/s$

Negative sign shows the opposite direction.

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$v=\sqrt{v_{x}^2+v_{y}^2}$

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Explanation:

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