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NemiM [27]
3 years ago
12

Two teams are playing tug of war. Team A pulls to the right with a force of 450 N. Team B pulls to the left with a force of 415

N. What is the net force on the rope, and what is its direction? 35 N to the right 35 N to the left 865 N to the right 865 N to the left
Physics
1 answer:
motikmotik3 years ago
6 0

Answer:

35 N to the right.

Explanation:

450 is going to the right so you subtract what is going against it. Which gives you 35. And because 450 is bigger than 415, it'll be going to the right.

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3 characteristics of physical change
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Answer:

Explanation:

A physical property is a characteristic of matter that is not associated with a change in its chemical composition. Familiar examples of physical properties include density, color, hardness, melting and boiling points, and electrical conductivity.

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3 years ago
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The pressure exerted by 15m of liquid is 1500pa.The acceleration due to gravity g=10m/s^2.Calculate the density liquid.​
Natali [406]

Answer:

1500 divided by 150(15m x 10m/s^2) = 10

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School homework about multiplying fractions <br><br>worth 30 brainly points​
RoseWind [281]

Answer:

Explanation:

1. \frac{1}{3} x \frac{6}{7} = \frac{6}{21}

          = \frac{2}{7}

b. \frac{6}{8} + \frac{4}{9} = \frac{24}{72}

            = \frac{1}{3}

c. \frac{10}{15} x \frac{3}{4} = \frac{30}{60}

            = \frac{1}{2}

d. \frac{7}{10} of \frac{5}{10} = \frac{7}{10} x \frac{5}{10}

                = \frac{35}{100}

                = \frac{7}{20}

e. \frac{3}{8} of \frac{4}{6} = \frac{3}{8} x \frac{4}{6}

            = \frac{12}{48}

            = \frac{1}{4}

f. \frac{7}{12} of \frac{9}{14} = \frac{7}{12} x \frac{9}{14}

              = \frac{63}{168}

              = \frac{3}{8}

2. \frac{22}{6} x \frac{3}{11} = \frac{66}{66}

              = 1

b. \frac{15}{6} x \frac{4}{5} = \frac{60}{30}

             = 2

c. \frac{25}{8} x \frac{4}{10} = \frac{100}{80}

              = \frac{5}{4}

d. \frac{33}{12} x \frac{4}{15} = \frac{132}{180}

             = \frac{11}{15}

4 0
3 years ago
A circular loop of flexible iron wire has an initial circumference of 165.0cm, but its circumference is decreasing at a constant
djverab [1.8K]

Answer:

0.005 V

Explanation:

We are given that

Initial circumference of circular loop=C=165 cm

Rate of circumference,\frac{dC}{dt}=12 cm/s

Magnetic field,B=0.5 T

We have to find the induced emf at time t=9 s

We know that induced amf,E=\frac{Bd(A)}{dt}

Area of circular coil,A=\pi r^2

E=B\frac{d(\pi r^2)}{dt}=B(2\pi r)\frac{dr}{dt}

Circumference of circular coil,C=2\pi r

165=2\pi r

r=\frac{165}{2\pi}

\frac{dr}{dt}=\frac{1}{2\pi}\frac{dC}{dt}=\frac{1}{2\pi}\times (12)=\frac{6}{\pi} cm/s=\frac{6\times 10^{-2}}{\pi} m/s

Radius of coil at time t=9 s

r=\frac{165}{2\pi}-(\frac{6}{\pi}\times 9)=9.08 cm=9.08\times 10^{-2} m

1 m=100 cm

E=-0.5(2\pi\times 9.08\times 10^{-2})\times \frac{6\times 10^{-2}}{\pi}=-0.005 V

Magnitude of induced emf=0.005 V

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Dennis_Churaev [7]

CH4+2O2=\ \textgreater \ CO2+2H2O
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3 0
3 years ago
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