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puteri [66]
3 years ago
13

A satellite is orbiting the Earth in a circular orbit of radius r. Its frequency is independent of its height above the surface

of the Earth. a. TRUE b. FALSE
Physics
1 answer:
Pie3 years ago
5 0

Answer:

a. TRUE

Explanation:

When a satellite is launched to orbit around earth, it has to produce its own artificial gravity by performing rotations. The frequency of this rotation is given by the following formula:

f = √[ac/4πR²]

where,

f = frequency

ac = centripetal acceleration

R = Radius of the satellite

Therefore, it is clear from this formula that the frequency of rotation of the satellite is independent of its height above the surface of earth. So, the correct option is:

<u>a. TRUE</u>

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Newton's first law of motion is the law of inertia. What does it state?
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Answer:

b is the right answer

Explanation:

<h3>hope helps!!</h3>
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3 years ago
A simple harmonic oscillator consists of a block (m = 0.50 kg) attached to a spring (k = 128 N/m). The block is pulled a certain
Zinaida [17]

Answer:

0.5 m

14.00595

8 m/s, 0.0625 s

5.71314 m/s

Explanation:

k = Spring constant = 128 N/m

A = Amplitude

E = Energy in spring = 16 J

Energy in spring is given by

E=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{2E}{k}}\\\Rightarrow A=\sqrt{\dfrac{2\times 16}{128}}\\\Rightarrow A=0.5\ m

The amplitude is 0.5 m

Time period is given by

T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{0.5}{128}}\\\Rightarrow T=0.39269\ s

Number of oscillations is given by

N=\dfrac{5.5}{0.39269}\\\Rightarrow N=14.00595

The number of oscillations is 14.00595

For maximum speed

\dfrac{1}{2}mv^2=16\\\Rightarrow v=\sqrt{\dfrac{16\times 2}{0.5}}\\\Rightarrow v=8\ m/s

The maximum speed is 8 m/s

For a distance of 0.5 m which is the amplitude

Time=\dfrac{Distance}{Speed}\\\Rightarrow Time=\dfrac{0.5}{8}\\\Rightarrow Time=0.0625\ s

The time taken would be 0.0625 s

The maximum kinetic energy is equal to the mechanical energy

\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2=16

At x = 0.35 m

v=\sqrt{\dfrac{16-\dfrac{1}{2}kx^2}{\dfrac{1}{2}m}}\\\Rightarrow v=\sqrt{\dfrac{16-\dfrac{1}{2}128\times 0.35^2}{\dfrac{1}{2}0.5}}\\\Rightarrow v=5.71314\ m/s

The speed of the block is 5.71314 m/s

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