All categories

2 years ago

Are the particles in a solid motionless ?

1 answer:

7 0

No. Just because it is a solid doesn't mean it has no motion. The only way for particles to be motionless is for the solid to reach Absolute Zero (0* K). Which is impossible. So, therefore, it is impossible for particles in a solid to be motionless.

You might be interested in

What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The latent heat of vaporization

zzz [600]

Answer:

$\boxed{\text{889 g}}$

Explanation:

The formula relating the mass m of a sample and the heat q to vaporize it is

q = mL, where L is the latent heat of vaporization.

$\begin{array}{rcl}2000 \times 10^{3} \text{ J} & = & m \times \dfrac{2.25 \times 10^{6} \text{ J}}{\text{1 kg}}\\\\m & = & \dfrac{2000 \times \times 10^{3}\text{ kg}}{2.25 \times 10^{6}}\\ & = & \text{0.889 kg}\\\\ & = & \text{889 g}\\\end{array}\\\text{The mass of water is $\boxed{\textbf{889 g}}$}$

5 0

2 years ago

Calculate Ho298 for the process

Inga [223]

Explanation:

As per the Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

Hence, according to this law the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

$Sb + \frac{3}{2}Cl_2 \rightarrow SbCl_{3}$ $\Delta H^0_1 = -314 kJ$ ..........(1)

$SbCl_{3} + Cl_2 \rightarrow SbCl_{5}$ $\Delta H^0_2 = -80kJ$ ..............(2)

The final reaction is as follows:

$Sb + \frac{5}{2}Cl_{2} \rightarrow SbCl_{5}$ $\Delta H^0_3 = ?$ .............(3)

Therefore, adding (1) and (2) we get the final equation (3) and value of $\Delta H^{0}_{3}$ at 298 K will be as follows.

$\Delta H^{0}_{3}$ = $\Delta H^{0}_{1}$ + $\Delta H^{0}_{2}$

= -314 kJ + (-80) kJ

= -394 kJ

Thus, we can conclude that $H^{o}$ at 298 K for the given process is -394 kJ.

4 0

3 years ago

Name the process by which the ammonia and hydrogen Chlorade gass nove in the tube-

____ [38]

Explanation: Process is diffusion. The gas molecules follow a zig-zag path through the tube as they collide with the air molecules in the tube. The purpose of the glass tube is to eliminate air currents and to see if the gas molecules will move on their own.

I guess this helped you

I hope you would mark me as BRAINLIEST!!

8 0

2 years ago

What is the molecular formula of the molecule that has an empirical formula of CH2O and a molar mass of 120.12 g/mol

ZanzabumX [31]

Answer:

C4H8O4

Explanation:

Let (CH20)x

C=1*12.01=12.01 (12.01, 1.01, 16.00 Avg mass of elements)

H=2*1.01=2.01

O=1*16.00=16.00

12.01 + 2.01 + 16.00 = 30.03

120.12/30,03=4

==> (CH2O)4 = C4H8O4

5 0

2 years ago

What is the correct unabbreviated electron configuration of the following?:

Rudik [331]

The correct unabbreviated electron configuration is as below

Vanadium - 1S2 2S2 2P6 3S2 3p6 3d3 4s2

Strontium - 1s2 2S2 2P6 3S2 3P6 3d10 4S2 4P6 4S2

Carbon =1S2 2S2 2P2

Explanation

vanadium is in atomic number 23 in the periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2

Strontium is in atomic number 38 in periodic table hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4s2

Carbon is in atomic number 6 in periodic table therefore its electron configuration is 1s2 2s2 2p2

5 0

3 years ago