fibrous roots; taproots
Explanation:
A taproot root consists of one large main root with smaller roots that branches off into the soil, while the fibrous roots consists of several main roots that branches off to form one mass of roots.
- The root system in plants helps them to absorb water and other nutrients from the soil.
- A taproot is much more like extension of stem that penetrates into the ground.
- It tapers at the end with many other smaller roots branching and networking from it.
- The fibrous root is a series of roots directly from the stem that independent of one another.
- Roots are used by plants for anchorage into the soil.
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Seedless vascular plants brainly.com/question/6047633
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<span>d. filters out harmful ultraviolet radiation</span>
Answer:
See explanation
Explanation:
In looking at molecules to determine whether they are polar or not we have to look at two things basically;
i) presence of polar bonds
ii) geometry of the molecule
Now, we know that CCI2F2 is a tetrahedral molecule, but the molecule is not symmetrical. It has four polar bonds that are not all the same hence the molecule is polar.
In an electric field, polar molecules orient themselves in such a way that the positive ends of the molecule are being attracted to the negative plate while the negative ends of the molecules are attracted to the positive plate.
So the positive ends of CCI2F2 are oriented towards the negative plate of the field while the negative ends of CCI2F2 are oriented towards the positive ends of the field.
Answer:
Explanation:
You don't give the reaction, but we can get by just by balancing atoms of Na.
We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
M_r: 142.04
2NaOH + … ⟶ Na₂SO₄ + …
n/mol: 0.75
1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.
Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH
= 0.375 mol Na₂SO₄
2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.
Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄
The reaction produces of Na₂SO₄.
