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2 years ago

The number of valence electrons in an element with electron configuration 1s2 2s2 2p6 3s2 3p4 is ________.

2 answers:

6 0

The element is Sulfur, the sixteenth element of the periodic table.

The way I found out was by adding up the number of electrons listed.
Electron configuration can be shown by listing the orbital and then the number of electrons in the group.
1s is the innermost orbital and holds 2 electrons, so a full 1s is shown as "1s2"
Using this logic, I found that there were 2 + 2 + 6 + 2 + 4 = 16 electrons total.
Each element has an amount of electrons equal to the number of protons, AKA the element's atomic number.
As the element with the atomic number 16 is Sulfur, it is our answer.

Monica [59]2 years ago

3 0

Answer:

Explanation:

The given electron configuration 1s² 2s² 2p⁶ 3s² 3p⁴.

The valence shell of an atom is the outermost orbit. Here the valence shell is 3 with electrons occupying the s and p orbitals.

The s orbital has 2 electrons and the 3p orbital has 6 electrons. So adding all the electrons in the 3s and 3p orbital we have a total of 6 electrons in the 3rd valence shell.

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Consider the following reaction where K. = 154 at 298 K: 2NO(g) + Brz(9) 2NOBr(g) A reaction mixture was found to contain 2.69x1

bekas [8.4K]

Explanation:

$2NO(g) + Br_2(g)\rightleftharpoons 2NOBr(g)$

Equilibrium constant of reaction = $K=154$

Concentration of NO = $[NO]=\frac{2.69\times 10^{-2} mol}{1 L}=2.69\times 10^{-2} M$

Concentration of bromine gas = $[Br_2]=\frac{3.85\times 10^{-2} mol}{1 L}=3.85\times 10^{-2} M$

Concentration of NOBr gas = $[Br_2]=\frac{9.56\times 10^{-2} mol}{1 L}=9.56\times 10^{-2} M$

The reaction quotient is given as:

$Q=\frac{[NOBr]^2}{[NO]^2[Br_2]}=\frac{(9.56\times 10^{-2} M)^2}{(2.69\times 10^{-2} M)^2\times 3.85\times 10^{-2} M}$

$Q=328.06$

$Q>K$

The reaction will go in backward direction in order to achieve an equilibrium state.

1. In order to reach equilibrium NOBr (g) must be produced. False

2. In order to reach equilibrium K must decrease. False

3. In order to reach equilibrium NO must be produced. True

4. Q. is less than K . False

5. The reaction is at equilibrium. No further reaction will occur. False

8 0

2 years ago

Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?

Ber [7]

Answer: C. The Number of Molecules

Explanation: I just took the test, it's correct.

6 0

3 years ago

Difference between giant ionic structure,giant covalent structure and simple molecular structure and also covalent bonds and ion

Alex_Xolod [135]

Simple molecular biology

8 0

2 years ago

The standard enthalpy of formation for glucose [c6h12o6(s)] is −1273.3 kj/mol. what is the correct formation equation correspond

balu736 [363]

The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is
C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is
6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)

Using the equation for the standard enthalpy change of formation
ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}

C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
= -1273.3 - (0 + 0 + 0)
= -1273.3

8 0

2 years ago

Las fórmulas actuales de los compuestos propuestos por Dalton

KonstantinChe [14]

Answer:

La teoría atómica de Dalton fue el primer intento completo para describir toda la materia en términos de los átomos y sus propiedades.

Dalton basó su teoría en la ley de la conservación de la masa y la ley de la composición constante.

La primera parte de su teoría establece que toda la materia está hecha de átomos, que son indivisibles.

La segunda parte de su teoría establece que todos los átomos de un elemento dado son idénticos en masa y en propiedades.

La tercera parte de su teoría establece que los compuestos son combinaciones de dos o más tipos diferentes de átomos.

La cuarta parte de su teoría establece que una reacción química es un reordenamiento de átomos.

Partes de su teoría tuvieron que ser modificadas con base en el descubrimiento de las partículas subatómicas y los isótopos.

6 0

2 years ago