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rusak2 [61]
3 years ago
14

The number of valence electrons in an element with electron configuration 1s2 2s2 2p6 3s2 3p4 is ________.

Chemistry
2 answers:
Natali5045456 [20]3 years ago
6 0
The element is Sulfur, the sixteenth element of the periodic table.

The way I found out was by adding up the number of electrons listed.
Electron configuration can be shown by listing the orbital and then the number of electrons in the group.
1s is the innermost orbital and holds 2 electrons, so a full 1s is shown as "1s2"
Using this logic, I found that there were 2 + 2 + 6 + 2 + 4 = 16 electrons total.
Each element has an amount of electrons equal to the number of protons, AKA the element's atomic number.
As the element with the atomic number 16 is Sulfur, it is our answer.
Monica [59]3 years ago
3 0

Answer:

6

Explanation:

The given electron configuration 1s² 2s² 2p⁶ 3s² 3p⁴.

The valence shell of an atom is the outermost orbit. Here the valence shell is 3 with electrons occupying the  s and p orbitals.

The s orbital has 2 electrons and the 3p orbital has 6 electrons. So adding all the electrons in the 3s and 3p orbital we have a total of 6 electrons in the 3rd valence shell.

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A chemist dissolves 614. mg of pure hydrochloric acid in enough water to make up 400 mL of solution. Calculate the pH of the sol
tatuchka [14]

Answer:

The pH of the solution is 1.38.

Explanation:

Mass of HCl = 614 mg = 0.614 g

Moles of HCl = \frac{0.614 g}{36.5 g/ mol}=0.01682 mol

Concentration of HCl :

Concentration =\frac{Moles}{\text{Volume of solution in L}}

On adding 0.01682 moles to 400 mL of water that 0.4 L of water.

[HCl]=\frac{0.01682 mol}{0.4 L}=0.04205 M

HCl(s)+H_2O(l)\rightarrow H_3O^+(aq)+Cl^-(aq)

1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.

Then 0.04205 mol/L of HCl will give:

1\times 0.04205 M =0.04205 mol/L of hydronium ions.

[H_3O^+]=0.04205 M

pH=-\log [H_3O^+]

pH=-\log [0.04205 M]=1.38

The pH of the solution is 1.38.

7 0
3 years ago
Explain why a single atom of hydrogen cannot produce all four hydrogen spectral lines simultaneously.
brilliants [131]
<span>When the electron in a hydrogen atom transitions from a high energy state to a lower energy state, the energy lost from the electron is used to produce a photon corresponding to the loss of energy. That photon will correspond to exactly 1 wavelength. And since a hydrogen atom has only 1 electron, at any given moment, it can only produce 1 photon. And in order to simultaneously produce 4 photons for 4 spectral lines, that would require a simultaneous transition of 4 electrons which is 3 too many for a hydrogen atom.</span>
7 0
3 years ago
(b) what is the major product of the reaction at very low temperatures?
svlad2 [7]
The reaction is low b/c of  the tempature. that's why.
8 0
3 years ago
1 loop in the primary coil and 8 loops in the secondary. If the secondary voltage is 120 V, what must be the primary voltage
Jet001 [13]

Answer:

V_{p} = 15 V

Explanation:

<u>Given the following data;</u>

Number of loops in primary coil, Np = 1 loop.

Number of loops in secondary coil, Ns = 8 loops

Voltage in secondary coil, Vs = 120V

To find the voltage in the primary coil, Vp;

Transformer ratio is given by the formula;

\frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}}

Making Vp the subject of formula;

V_{p} = \frac{N_{p}}{N_{s}} * V_{s}

Substituting into the equation, we have;

V_{p} = \frac{1}{8} * 120

V_{p} = \frac{120}{8}

V_{p} = 15 V

Therefore, the voltage in the primary coil, Vp is 15 Volts.

4 0
2 years ago
Ethylene glycol (C2H6O2) is used as an antifreeze in cars. If 250 g of ethylene glycol is added to 3.00 kg of water, what is the
Zepler [3.9K]

Answer:

2,909 M

Explanation:

molair mass is of.ethylene is 26,04 g/mol

first you need to calculate how much mL 3 kg is. You can do this by using the density of ethylene: 1,1 g/mL.

3000 g x 1.1 = 3300 mL = 3,3 L

Next you need to calculate the amount of moles:

250 g / 26,04 g/mol = 9,60 mol

Now you can calculate the molarity:

9,6/3.3 = 2,909 M

I don't know the answer for the second question. I'm sorry.

3 0
3 years ago
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