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rusak2 [61]
2 years ago
14

The number of valence electrons in an element with electron configuration 1s2 2s2 2p6 3s2 3p4 is ________.

Chemistry
2 answers:
Natali5045456 [20]2 years ago
6 0
The element is Sulfur, the sixteenth element of the periodic table.

The way I found out was by adding up the number of electrons listed.
Electron configuration can be shown by listing the orbital and then the number of electrons in the group.
1s is the innermost orbital and holds 2 electrons, so a full 1s is shown as "1s2"
Using this logic, I found that there were 2 + 2 + 6 + 2 + 4 = 16 electrons total.
Each element has an amount of electrons equal to the number of protons, AKA the element's atomic number.
As the element with the atomic number 16 is Sulfur, it is our answer.
Monica [59]2 years ago
3 0

Answer:

6

Explanation:

The given electron configuration 1s² 2s² 2p⁶ 3s² 3p⁴.

The valence shell of an atom is the outermost orbit. Here the valence shell is 3 with electrons occupying the  s and p orbitals.

The s orbital has 2 electrons and the 3p orbital has 6 electrons. So adding all the electrons in the 3s and 3p orbital we have a total of 6 electrons in the 3rd valence shell.

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Astatine belongs to which element group: nonmetal, halogen, noble gas?
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Answer:

halogen

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It belongs to Group 17 on the periodic table, which is a halogen

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3 years ago
Why does an atom of 23NA have 23 electrons
Julli [10]
It is actually something standardized more so than theoretical,  however in terms of atoms in general the electrons are based on the amount of  electronic shells that an atom has and the amount of electrons that atom can accommodate.  In the case of sodium, it has three shells with 2 electrons on the first shell which is the maximum, 8 on the second shell which is also the max and 1 on their final shell
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3 years ago
You wish to make a 0.285 M hydroiodic acid solution from a stock solution of 12.0 M hydroiodic acid. How much concentrated acid
Inessa05 [86]

The amount, in mL, of the concentrated acid required, would be 1.1875 mL

<h3>Dilution</h3>

From the dilution equation:

m1v1=m2v2 where m1 and m2 = molarity before and after dilution, and v1 and v2 = volume before and after dilution.

m2 = 0.285M, m1 = 12.0M v2 = 50.0 mL

v1 = m2v2/m1 = 0.285x50/12 = 1.1875 mL

Thus, 1.1875 mL of the acid would be taken and diluted with water up to the 50 mL mark.

More on dilution can be found here: brainly.com/question/13949222

#SPJ1

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2 years ago
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Katen [24]

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2 years ago
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To reduce competition, an organism can do which of the following?
andrew-mc [135]

Answer:

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