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Ira Lisetskai [31]
4 years ago
15

A small uniform disk and a small uniform sphere are released simultaneously at the top of a high inclined plane, and they roll d

own without slipping. Which one will reach the bottom first?A) the one of smallest diameter B) the one of greatest mass C) the disk D) the sphere E) They will reach the bottom at the same time.
Physics
1 answer:
barxatty [35]4 years ago
3 0

Answer:

(D) the sphere

Explanation:

The bodies given are Disk and Solid sphere (uniform sphere)

Moment of inertia of the bodies are

I(disk) = \frac{MR^2}{2}

I(sphere) = \frac{2MR^2}{5}

Since the moment of inertia of sphere is less than that of disk, therefore sphere will reach the bottom first.

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What might you be doing if you measure your heart rate and find that it beats 100 times in a minute?
alisha [4.7K]

Answer:

Rigorous exercise

Explanation:

For your heart rate is been around 100 bpm you should be doing a rigorous exercise . but if ain't doing any rigorous exercise and your heart rate is constantly above 100 bpm you should consult your doctor.

An average heart is between 60 bpm to 100 bpm.

6 0
3 years ago
Application - You have two objects that you want to push the same distance (5 meters) across the floor. The objects have differe
Mamont248 [21]

I see you're in Middle School, so I've got a hunch that they want you
to say "the dresser because it has more mass".  But that's a poor
answer, to a poor question.

The fact is that there's no way to tell.

The force it takes to move either object across the floor does NOT really
depend on just its mass.  It depends on both the object's mass AND the
friction between the object and the floor.  And THAT depends on the shape
of the feet where they touch the floor, and what kind of material the feet and
the floor are made of.

So it seems to me that we really don't have enough information to answer
the question with.

But again, I suspect that the answer they want is "the dresser because
it has more mass".

8 0
3 years ago
A helium balloon has a radius of 2m. The density of helium of helium is 0.17 kg/m3 and the density of air is 1.25 kg/m3. What is
3241004551 [841]

To solve this problem we will begin by finding the force on each of the elements. For this it will be necessary to obtain the mass, which can be related to density and volume. Finally, by balancing forces it will be possible to obtain the final value of the maximum mass that can be lifted.

By Newton's second law we have,

F = mg

Here,

g = Gravitational acceleration

m = mass

At the same time mass can be described as,

m_1 = \rho \times V

m_1 = (1.25)\times \frac{4}{3} (2)^2

Therefore the Force 1 is,

F = m_1 g

F = \frac{40\pi }{3} (9.8)

F = 410.501N

Applying the same concepto but for the second mass we have,

m_2 = \rho \times V

m_2 = (0.17) \times \frac{3}{4} \pi 2^2

m_2 = 5.697kg

Now by equilibrium we have,

W + mg = F

m = \frac{F+W}{g}

m = \frac{410.501-55.828}{9.8}

m = 36.19kg

Therefore the maximum mass lift by balloon is 36.19kg

3 0
4 years ago
A charge of −25µC is distributed uniformly over the surface of a spherical conductor of radius 12.0 cm. Determine the electric f
Bond [772]

Answer:

a) 0 b) 0 c) -9*10⁵ N/C

Explanation:

a)

  • In electrostatic conditions, no electric field can exist inside a conductor.
  • As the distance r=5 cm falls inside the conductor, the electric field is just zero.

b)

  • Same as above, as r=10 cm is still inside the spherical conductor.

c)

  • At r= 50 cm. from the center of the spherical conductor, we can apply Gauss' Law in order to get the value of the electric field.
  • By symmetry, the electric field, at a same distance from the center, must be radial, and constant on a spherical surface concentric with the spherical conductor.
  • So, we can write the following equation for Gauss'Law:

       \int\ {E} \, dA = \frac{Q}{\epsilon_{0} }

  • If E is constant, we can take it out of the integral, and integrate all the closed spherical surface, as follows:

       E* 4*\pi *r^{2}  =\frac{Q}{\epsilon_{0}}

  • So, we can solve for E, as follows:

       E = \frac{Q}{4*\pi*r^{2}*\epsilon_{0}} =  \frac{(-25e-6)C}{4*\pi*(0.5m)^{2}*8.85e-12C2/N*m2}}\\\\   E = -9e5 N/C

  • E = -9*10⁵ N/C (radially inward, taking the outward direction as positive)
8 0
3 years ago
How is an interference pattern formed by a diffraction grating different from the pattern formed by a double slit
belka [17]

Answer:

Evaluate the following numerical expressions.

6 + 3 • 4 =

18

(6 + 3) ÷ (4 – 5) =

Explanation:

Evaluate the following numerical expressions.

6 + 3 • 4 =

18

(6 + 3) ÷ (4 – 5) =

8 0
2 years ago
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