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BartSMP [9]
3 years ago
13

Please help!!! give me a summary on why human population is either good or bad!! thank youu

Physics
1 answer:
bagirrra123 [75]3 years ago
7 0
It is bad because humans are destroying the planet with pollution and cutting down natural habitats. This is not only killing the human population in the future, but as of right now they are killing animals, and trees. The human population is slowly destroying the planet.
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Fuel cells have been developed that can generate a large amount of energy. For example, a hydrogen fuel cell works by combining
maksim [4K]
Electric power is given by:
Power = voltage x current
10000 = 15.8V
V = 633 Volts
7 0
4 years ago
Stars originate as large bodies of slowly rotating gas.Because of gravity, these clumps of gas slowly decrease in size.The angul
Tamiku [17]

Answer:

E.) conservation of angular momentum

Explanation:

The angular momentum is defined as:

L=r x mv

where r is the radius of the star, m is the mass and v the angular velocity.

and angular momentum is an amount that is conserved, so the angular momentum before the star is compressed must be equal to the angular momentum after the star was compressed:

r_{1} x mv_{1}=r_{2} x mv_{2}

the second radius is smaller than the first radius, since the star shrinked, the second angular velocity must be greater that the first.

In other words, the angular velicity increases as the star shrinks because of the conservation of angular momentum.

4 0
3 years ago
PLEASE HELPPP ASAP
vodomira [7]

Answer:

F = 12.5N

Explanation:

Force (F) = Mass (m) x Acceleration (a)

F = ma

F = (2.5kg) x (5m/s^2)

F = 12.5N

6 0
3 years ago
A small racquet ball launcher is set up 5 meters from a 12 meter tall wall. It launches a racket ball at 30 m/s at an angle of 4
Strike441 [17]

Answer:20.82 m

Explanation:

Given

distance between wall and launcher=5 m

initial velocity=30 m/s

Launching angle=45^{\circ}

Height of wall=12 m

maximum height by ball

h_{max}=\frac{u^2sin^2\theta }{2g}

h_{max}=\frac{30^2sin^{2}45}{2\times 9.8}

h=22.95 m

y=xtan\theta -\frac{gx^2}{2u^2cos^\theta }

y=4.72 m

so ball will strike with wall

and for perfect restitution final velocity of ball will be same as the horizontal velocity before its impact, only direction will be opposite and vertical velocity will be zero

thus it seems as if someone throw the ball with horizontal velocity of 30cos45 from a height of 4.72

Time required to cover 4.72 m

t=\sqrt{\frac{2h}{g}}

t=\sqrt{\frac{9.45}{9.8}}

t=0.981 s

Horizontal distance traveled in this time

R=ucos45\times t

R=30\times cos45\times 0.981

R=20.82 m

6 0
3 years ago
A cheetah goes from 0m/s to 25m/s in 2.5 s. What is the cheetah's rate of acceleration?
RUDIKE [14]

Answer:

10 m/s²

Explanation:

Acceleration: This the rate of change of velocity. The unit of acceleration is m/s²

From the question,

a = (v-u)/t.................... Equation 1

Where a = acceleration of the cheetah, v = final velocity of the cheetah, u = initial velocity of the cheetah, t = time.

Given: u = 0 m/s, v = 25 m/s, t = 2.5 s.

Substitute these values into equation 1

a = (25-0)/2.5

a = 25/2.5

a = 10 m/s²

Hence the acceleration of the cheetah = 10 m/s²

6 0
3 years ago
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