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JulsSmile [24]
3 years ago
5

Calculate the value of 200°C in Kelvin

Physics
1 answer:
Elan Coil [88]3 years ago
3 0

Answer:

473.15

Explanation:

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A uniform cylindrical grindstone has a mass of 10 kg and a radius of 12 cm. (a) What is the rotational kinetic energy of the gri
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Answer:

a) KE = 888.26J

b) N = 294.5 turns

Explanation:

For the kinetic energy:

KE = I/2*\omega_o^2

The inertia is:

I=m/2*R^2=0.072kg.m^2

So, the kinetic energy will be:

KE = 888.26J

Now, friction force is:

Ff = μ*N = 0.80*5N = 4N

The energy balance would be:

Kf - Ko = Wf    where Kf=0;   Ko = 888.26J;  and Wf is the work done by friction force.

Wf = -Ff*d = -Ff*N*2*π*R   where N is the amount of turns it gives.

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0-888.26=-4*N*2*π*0.12

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Within a vacuum, the property to all electromagnetic waves is their
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In what direction would the particles in this wave move, relative to the direction of wave travel?
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