Calculate the value of 200°C in Kelvin
1 answer:
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Answer:
Induced current I = 0.44 A
Explanation:
given data
no of turn N = 18
radius = 27.0 cm
resistance of the coil = 4.50 Ω
time = 2.90 s
magnetic field = 1.90 T to 0.500 T
solution
we get Induced EMF that is
E = - dφ ÷ dt ..............1
E = - N × A × (B2 - B1) ÷ Δt
E = N × A × (B1 - B2) ÷ Δt
area of cross section of the coil A = π × r²
area of cross section = 3.14 × (0.27)²
area of cross section = 0.228 m²
Initial magnetic field B1 = 1.9 T
and
Final magnetic field B2 = 0.5 T
time Δt = 3.7 s
put here value and we get
E =
E = 1.98 V
and
Induced current I is express as
Induced current I = E ÷ R ................2
Induced current I =
Induced current I = 0.44 A