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natita [175]
2 years ago
13

4.2.5 quiz waves and technology

Physics
1 answer:
kolezko [41]2 years ago
6 0

Answer:

What’s the Question

Explanation:

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If an object starts from rest, what is its initial velocity?
Vladimir79 [104]

Answer:

0 m/s

Explanation:

velocity= change in displacement/ time

at rest, the ball does not travel any distance

0/ t

=0

4 0
3 years ago
What type of lens does our eye function as, and what is it's purpose?
yKpoI14uk [10]
It is D because our eye lenses reflect the white light we see and it also reflects the light to a point to where we can see colors and objects clearly... Hope this helps out ^-^''
3 0
3 years ago
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Why does it take much longer time and distance to stop a moving ship in water than a moving car on the road
Naddik [55]
The force on the ship is more than a car
6 0
3 years ago
With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be
Delvig [45]

Answer:

The resistance must be 6.67\Omega

Solution:

Resistance, R_{1} = 20\Omega

Resistance, R_{2} = 10\Omega

For the current to be the same when the switch is open or closed, the resistances must be connected in parallel as current is distributed in parallel with the same voltage across the circuit:

Thus in parallel:

\frac{1}{R_{eq}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}

\frac{1}{R_{eq}} = \frac{1}{20} + \frac{1}{10}

R_{eq} = 6.67\ \Omega

4 0
3 years ago
As an intern at an engineering firm, you are asked to measure the moment of inertia of a large wheel for rotation about an axis
klio [65]

Hi there!

We can begin by finding the acceleration of the block.

Use the kinematic equation:

d = v_0t + \frac{1}{2}at^2

The block starts from rest, so:

d = \frac{1}{2}at^2\\\\12 = \frac{1}{2}a(4^2)\\\\\frac{24}{16} = a = 1.5 m/s^2

Now, we can do a summation of forces of the block using Newton's Second Law:

F = ma = m_bg - T

mb = mass of the block

T = tension of string

Solve for tension:

T = m_bg - ma = 8.2(9.8) - 8.2(1.5) = 68.06 N

Now, we can do a summation of torques for the wheel:

\Sigma \tau = rF\\\\\Sigma\tau = rT

Rewrite:

I\alpha = rT

We solved that the linear acceleration is 1.5 m/s², so we can solve for the angular acceleration using the following:

\alpha = a/r\\\\\alpha = 1.5/.42= 3.57 rad/sec^2

Now, plug in the values into the equation:

I(3.57) = (0.42)(68.06)\\\\I = (0.42)(68.06)/(3.57) = \boxed{8.00 kgm^2}

8 0
2 years ago
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