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daser333 [38]
3 years ago
6

Which of these characteristics do these elements have in common?

Chemistry
1 answer:
Over [174]3 years ago
6 0

C) They each form similar compounds when combined with oxygen.

Explanation:

The given elements have a common characteristics as they each form similar compounds when combined with oxygen.

Beryllium, magnesium and calcium all are located in the alkaline earth group.

Elements in the same group have the same chemical properties.

  • Density and melting point are physical properties of matter which varies down a group on the periodic table.
  • Their reaction with oxygen denotes a statement of their chemical properties.
  • Chemical properties of matter is a function of their valency.
  • Group two elements have a valency of two. They have two electrons in their outermost shell.
  • Therefore, they all form ionic bonds when they react with oxygen.

learn more:

Periodic table brainly.com/question/2690837

#learnwithBrainly

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Which gas has the highest diffusing rate between nitrogen , oxygen , hydrogen and chlorine
Vilka [71]

Answer:

hydrogen

Explanation:

The gas with the least molecular weight effuses the fastest (Graham's Law). Hence, H gas has a higher rate of diffusion compared to N, O, and Cl.

So, Cl is the slowest when it comes to the rate of diffusion, because it has the highest molecular weight.

7 0
2 years ago
To separate solid particles from a liquid, you would use:
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Filtration

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3 0
3 years ago
Which state of matter is charcterized with no volume?
ziro4ka [17]

The answer is GAS. Gas has a physical state characterized by having no definite volume or shape and consisting of neutral particles. or it can also be plasma.



7 0
3 years ago
1.How many mL of 0.401 M HI are needed to dissolve 5.97 g of BaCO3?
garri49 [273]

Answer:

The answer to your question is:

1.- volume = 0.151 l or 151 ml

2.- 0.241 l  or 241 ml of NaOH

Explanation:

1.-

Data

V = ? HI = 0.401 M

BaCO3 = 5.97 g

                     2HI(aq)    +    BaCO3(s)   ⇒   BaI2(aq) + H2O(l) + CO2(g)

MW BaCO3 = 137 + 12 + 48 = 197 g

                     197 g of BaCO3 ----------------- 1 mol

                     5.97 g                -----------------   x

                     x = (5.97 x 1) /197

                    x = 0.03 mol of BaCO3

                    2 moles of HI ----------------  1 mol of BaCO3

                    x                     ----------------  0.03 mol of BaCO3

                    x = (0.03 x 2) / 1

                   x = 0.060 mol of HI

Molarity = moles / volume

volume = moles / molarity

volume = 0.060 / 0.401

volume = 0.151 l or 151 ml

2.-

V = ?    NaoH 0.757 M

Co⁺² Volume = 167 ml   0.548 M

             CoSO4(aq) + 2NaOH(aq)   ⇒   Co(OH)2(s) + Na2SO4(aq)

Moles of Co = Molarity x  volume

Moles of Co = 0.548 x 0.167

Moles of Co = 0.092

                                 1 mol of CoSO4 -------------- 2 moles of NaOH

                                0.092 moles      ---------------   x

                                x = (0.092 x 2) /1

                               x = 0.183 moles of NaOH

Volume of NaOH = moles / molarity

                             = 0.183 / 0.757

                            = 0.241 l  or 241 ml of NaOH

6 0
3 years ago
Calculate the number of moles in 456 grams of lead, Pb
Kamila [148]
Mass 456
relative mass 82
moles
mass = rm x moles
456/82 = 5.5609756....
8 0
3 years ago
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